In this article, we will enhance our understanding of arrays and lists through algorithm problems and explore various techniques useful when dealing with arrays and lists. Arrays and lists are fundamental and essential parts of data structures, frequently encountered in coding tests. This course will select one algorithm problem and explain the process of solving it step by step.
Problem Description
The following is the “Problem of finding a specific number pair in a given array.”
Problem: Two Sum
Given an integer array nums
and an integer target
,
write a function that returns the indices of the two numbers such that they add up to target
.
For example, if nums = [2, 7, 11, 15]
and target = 9
,
the output should be [0, 1]
. (2 + 7 = 9)
Approach to the Problem
To solve this problem, several strategies can be considered. The approaches are as follows:
- Brute Force Method: Use two nested loops to check the sum of all pairs. This has a time complexity of O(n^2).
- Using HashMap: Iterate through the numbers, storing the index of the current number in a hash map and checking if
target - current number
exists in the hash map. This has a time complexity of O(n).
Solution Method
The second method of using a hash map is more efficient, so let’s use this method to solve the problem.
First, based on the given array and the target, we will follow these steps:
Step 1: Initialization
Initialize an empty hash map and set up variables to find the sum of two numbers while iterating through the array.
Step 2: Iterate through Numbers
While checking each number in the array, first check if the complement of the current number exists in the hash map.
If it does, return that index as the result. If not, add the current number and its index to the hash map.
Step 3: Return the Result
After iterating through all the numbers, if no two numbers are found that sum up to target
, it does not meet the problem’s requirements.
Code Implementation
Implementing the above approach in code would look like this:
def two_sum(nums, target):
num_map = {}
for index, num in enumerate(nums):
complement = target - num
if complement in num_map:
return [num_map[complement], index]
num_map[num] = index
return []
Code Explanation
In the above code, the two_sum
function takes two parameters nums
and target
.
It initializes an empty hash map called num_map
and iterates through nums
using the enumerate
function.
For each number, it calculates the complement
and searches for that value in the hash map.
If found, it returns a list containing the index of that number and the current index.
If not found after checking all, it returns an empty list.
Complexity Analysis
The time complexity of this algorithm is O(n), and the space complexity is O(n).
This is due to all numbers and indices stored in the hash map.
This method is designed to efficiently find the desired pairs in the given array.
Conclusion
Arrays and lists are fundamental elements in data processing and play a significant role in various algorithm problems.
In this course, we learned how to efficiently solve the problem of “Two Sum” by exploring array indices and utilizing hash maps.
This will help save time and resolve problems in actual coding test situations.
In the future, we will deepen our understanding of data structures such as arrays, lists, and hash maps through various algorithm problems.
With continuous practice and problem-solving, I hope to become a more skilled coder. Thank you.