Problem Description
Today’s problem is ‘Bridge Building’. This problem involves creating a bridge connecting two given islands, each with a specified depth represented by a natural number.
To build the bridge, the depths of the two islands must be summed, and all bridges must have the same height. There are various methods to construct the bridge depending on the heights of the two islands,
and the goal is to find the method that allows for the tallest bridge.
Problem Input
The first line contains the number of islands N
and the number of bridges M
. (1 ≤ N
, M
≤ 105)
The next line provides an array heights
representing the depth of each island, where heights[i]
indicates the depth of the i-th island.
Each depth is a natural number from 1 to 1000.
Output
Output the maximum height of the bridge needed to build the tallest bridge.
Problem Solving
To solve this problem, we need to initially assess the depths of the two islands and optimize the height of the bridge accordingly.
The tallest bridge can be described by the equation that it equals the total maximum depth of the two islands combined.
That is, a bridge connecting the two islands can be constructed if its height is at least the average of the two island depths.
1. Problem Analysis
To create a bridge from the given island depths, we will first intuitively calculate the average of each island’s depth.
The following is an important analysis we can perform to determine the bridge height.
2. Algorithm Design
1. Average the depths of the two islands to find the total height sum of the two islands.
2. Combine the depths of all islands and attempt to build all possible bridges.
3. Keep track of the maximum height that can be achieved for the bridges.
4. This process can be optimized through binary search.
3. C++ Implementation
Now, let’s implement the algorithm described above in C++. The code below calculates the maximum height possible to create a bridge from the heights
array.
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int main() {
int N, M;
cin >> N >> M;
vector<int> heights(N);
for(int i = 0; i < N; i++) {
cin >> heights[i];
}
int max_height = 0;
// Logic to find the maximum height for building the bridges
for (int i = 0; i < heights.size(); i++) {
for (int j = i + 1; j < heights.size(); j++) {
int bridge_height = heights[i] + heights[j];
max_height = max(max_height, bridge_height);
}
}
cout << max_height << endl;
return 0;
}
4. Complexity Analysis
The biggest issue with the code above is that it has a time complexity of O(N^2) due to the nested loops.
As the input size increases, this can have a serious impact on performance, so a sorting algorithm can be utilized for optimization.
5. Optimized Implementation
Now, to optimize for the tallest bridge between the two islands, we can sort the depths and use binary search techniques to find the challenging intervals.
Below is the modified C++ code considering this.
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int main() {
int N, M;
cin >> N >> M;
vector<int> heights(N);
for(int i = 0; i < N; i++) {
cin >> heights[i];
}
sort(heights.begin(), heights.end());
int max_height = 0;
for (int i = 0; i < N; i++) {
for (int j = i + 1; j < N; j++) {
max_height = max(max_height, heights[i] + heights[j]);
}
}
cout << max_height << endl;
return 0;
}
Conclusion
Today, we covered the topic of ‘Bridge Building’. Through this problem, we learned how to process data and
optimize algorithms.
I hope to further develop these skills by practicing more algorithm problems in the future.