Swift Coding Test Course, Segment Tree

Hello! In this lecture, we will take a closer look at the segment tree, which is one of the data structures. The segment tree is a powerful data structure that can efficiently handle interval queries, especially useful for calculating the range sum, range minimum, and range maximum of an array. In this text, we will explore the basic concepts of segment trees, how to implement them, and solve problems that are frequently asked in practice.

1. What is a Segment Tree?

A segment tree is a powerful tool for efficiently managing the interval information of an array. Typically, when the size of the array is N, a segment tree uses approximately 2 * 2⌈log₂(N)⌉ memory space. This is due to the use of a complete binary tree structure. Fundamentally, the segment tree can perform the following two operations efficiently:

  • Interval Query: Quickly retrieve information about a specific interval.
  • Update: Rapidly update the interval information affected after changing a specific element of the array.

2. Structure of the Segment Tree

The segment tree is made up of nodes, each representing a specific interval. For example, there is a root node that manages the interval from index 0 to N-1 of the array, and this node divides the array into two halves through two child nodes. By continuously dividing the array in this manner, each node holds the information of a specific interval.

2.1 Node Definition

Each node contains the following information:

  • Start Index (start): The starting point of the interval
  • End Index (end): The ending point of the interval
  • Value (value): A variable to store the information of the interval (e.g., sum, minimum value, etc.)

3. Creating and Querying the Segment Tree

To implement a segment tree, we first need to build the tree. For this, we use a method that recursively creates segment tree nodes based on the input array. As a simple example, let’s create a segment tree for range sums.


// Swift Code
class SegmentTree {
    var tree: [Int] // Array to store the segment tree
    var n: Int // Size of the array

    init(_ data: [Int]) {
        self.n = data.count
        self.tree = Array(repeating: 0, count: 4 * n) // Initialize the tree array
        buildTree(data: data, node: 1, start: 0, end: n - 1)
    }

    // Build the segment tree using the interval of the array
    func buildTree(data: [Int], node: Int, start: Int, end: Int) {
        if start == end {
            tree[node] = data[start] // Store value in leaf node
        } else {
            let mid = (start + end) / 2
            buildTree(data: data, node: 2 * node, start: start, end: mid) // Left subtree
            buildTree(data: data, node: 2 * node + 1, start: mid + 1, end: end) // Right subtree
            tree[node] = tree[2 * node] + tree[2 * node + 1] // Update parent node value
        }
    }
}

4. Processing Segment Tree Queries

The segment tree now needs to add a feature to calculate range sums. To handle range sum queries, we will add the following function:


// Function to calculate the sum of a given interval
func query(node: Int, start: Int, end: Int, l: Int, r: Int) -> Int {
    if r < start || end < l { // If intervals do not overlap
        return 0 // Default value
    }
    if l <= start && end <= r { // If the interval is completely contained
        return tree[node]
    }
    let mid = (start + end) / 2
    let leftSum = query(node: 2 * node, start: start, end: mid, l: l, r: r) // Query left subtree
    let rightSum = query(node: 2 * node + 1, start: mid + 1, end: end, l: l, r: r) // Query right subtree
    return leftSum + rightSum // Sum the results
}

5. Updating the Segment Tree

We will also add a function to update the elements of the array. When changing a specific index of the array, here’s how we can quickly update the information in the segment tree:


// Function to update a specific index of the array
func update(node: Int, start: Int, end: Int, idx: Int, value: Int) {
    if start == end { // Reached leaf node
        tree[node] = value // Update the node
    } else {
        let mid = (start + end) / 2
        if start <= idx && idx <= mid {
            update(node: 2 * node, start: start, end: mid, idx: idx, value: value) // Update left subtree
        } else {
            update(node: 2 * node + 1, start: mid + 1, end: end, idx: idx, value: value) // Update right subtree
        }
        tree[node] = tree[2 * node] + tree[2 * node + 1] // Update parent node value
    }
}

6. Example of a Practical Problem

Now that we have looked at the basic structure of the segment tree and how to perform queries and updates, let's tackle a problem that is frequently asked in practice. The problem is as follows:

Problem Description

Given an array, answer the following questions:

  1. Calculate the sum of the interval [L, R].
  2. Update the value of index I to V.

Input Format

N (array size)
arr[0], arr[1], ..., arr[N-1]
Q (number of queries)
Each query is given in the following format:
1 L R (range sum query)
2 I V (update query)

Output Format

Output for each range sum query

Example

5
1 2 3 4 5
3
1 1 3
2 2 10
1 1 3
Example Output
6

7. Problem-Solving Process

  1. Build a segment tree for the input array.
  2. Depending on the query type, call the query() function for range queries and the update() function for update queries.
  3. Print the results.

// Main function to solve the problem
import Foundation

func main() {
    // Input processing
    let n = Int(readLine()!)!
    let arr = readLine()!.split(separator: " ").map { Int($0)! }
    let q = Int(readLine()!)!

    // Build the segment tree
    let segmentTree = SegmentTree(arr)

    // Process queries
    for _ in 0..

8. Conclusion

Through this lecture on segment trees, we learned the importance of data structures and how to utilize them. Segment trees can be effectively used for various interval query problems. We hope you will enhance your skills in applying segment trees through more practice problems. Thank you!

Swift Coding Test Course, Selection Sort

Hello! In this blog, I will conduct a coding test preparation algorithm lecture for developers using Swift. The topic is ‘Selection Sort’. Selection Sort is a sorting algorithm that helps to understand the basic concepts of algorithms. In this article, I will explain the definition of selection sort, how it works, how to implement it in Swift, and how to solve problems using it in detail.

1. What is Selection Sort?

Selection sort is one of the simple sorting algorithms, which sorts a given list by finding the smallest (or largest) element and swapping it with the first element of the list. Selection sort performs sorting through the process of repeatedly selecting from the entire list.

How Selection Sort Works

  1. Find the smallest value in the list.
  2. Swap the found value with the first element of the list.
  3. Find and swap the smallest value again from the rest of the list, excluding the first element.
  4. Repeat this process until the list is sorted.

2. Time Complexity of Selection Sort

The time complexity of selection sort is O(n2). This is due to the operation of two nested loops. Selection sort exhibits a performance of O(n2) in both the best and worst case. Therefore, it can become inefficient as the number of data increases.

3. Implementing in Swift

Now let’s implement selection sort in Swift. Below is an example of a function that sorts an array using the selection sort method:


func selectionSort(_ array: inout [Int]) {
    let count = array.count
    for i in 0..

3.1 Explanation

Here is a detailed explanation of the functionality of this code:

  1. func selectionSort(_ array: inout [Int]) {: Defines the selection sort function and takes the array to be sorted as input. The inout keyword allows modification of the array within the function.
  2. let count = array.count: Stores the number of elements in the array.
  3. for i in 0..: Iterates through the array indices one by one. In selection sort, the minimum value is found for each position.
  4. var minIndex = i: Initializes the current index i as the minimum value index.
  5. for j in (i + 1)..: Iterates through the indices from i + 1 to count to find the minimum value.
  6. if array[j] < array[minIndex] { minIndex = j }: Updates minIndex if the current value being compared is smaller than the previous minimum value.
  7. if minIndex != i { array.swapAt(i, minIndex) }: Swaps the two values if the current minimum value's position is different from i.

4. Algorithm Problem Utilizing Selection Sort

Now, I will introduce an actual problem where selection sort can be applied.

Problem: Sort an Array of Integers

Given an array of integers, use selection sort to sort the array in ascending order.

Function Definition

Let's look at the definition of a Swift function that performs the given functionality.


func sortArrayWithSelectionSort(array: [Int]) -> [Int] {
    var sortedArray = array
    selectionSort(&sortedArray)
    return sortedArray
}

5. How to Use the Selection Sort Function

Here is how to use the selection sort function to sort an array.


let unsortedArray = [64, 25, 12, 22, 11]
let sortedArray = sortArrayWithSelectionSort(array: unsortedArray)
print(sortedArray)  // Output: [11, 12, 22, 25, 64]

6. Conclusion

In this lecture, we explored the principles of the selection sort algorithm and how to implement it in Swift. While selection sort is not highly complex by itself, it is not the most efficient sorting method in practice. However, by understanding its simple principles, you should have been able to grasp the flow of basic algorithms.

I hope that with further study of various sorting methods and a better understanding of more complex algorithms and data structures, you will perform excellently in interviews and coding tests.

References

Swift Coding Test Course, Determining Line Segment Intersection

Hello! In this post, we will solve the ‘Determining the Intersection of Line Segments’ problem that is frequently asked in coding interviews using Swift. Through this problem, we will understand the basic concepts of algorithms and discuss how to solve the problem.

Problem Description

Given two line segments AB and CD, the problem is to determine whether these two segments intersect. Here, line segment AB is composed of point A(x1, y1) and point B(x2, y2), and line segment CD is composed of point C(x3, y3) and point D(x4, y4). Your goal is to verify whether AB and CD intersect and to return the result as a Boolean value.

The conditions for line segments to cross each other are as follows:

  • When distinct segments block each other
  • When endpoints lie on the other segment

Approach to the Problem

To solve this problem, we need to utilize geometric properties. Generally, to determine whether two segments intersect, we can use linear methods and cross-verification. The basic idea is to have arrays of points that define each segment and ensure that the segments can be expressed by equations.

The fundamental principle for determining line intersection is to use the direction of vectors to check whether each segment blocks the other. After defining each segment, we need to create a function to determine whether they intersect.

Algorithm Design

First, let’s figure out how to compute the direction of the two segments. Assume we have two given points A(x1, y1), B(x2, y2) and C(x3, y3), D(x4, y4). We can use the cross product to find the relative positions of the two points.

The cross product is defined as follows:

                (B - A) × (D - A) 
            

Through the cross product of the vectors, we can determine the orientation of the two segments. The next step is to check whether the segments intersect.

The function to implement is as follows:

  1. Calculate the cross product of the two points.
  2. Determine the intersection of the segments based on the results.
  3. Return a Boolean value according to each case.

Swift Code Example

Now, based on the above algorithm, let’s write the code in Swift.

                
                struct Point {
                    var x: Double
                    var y: Double
                }

                func orientation(p: Point, q: Point, r: Point) -> Int {
                    let val = (q.y - p.y) * (r.x - q.x) - (q.x - p.x) * (r.y - q.y)
                    if val == 0 { return 0 // Collinear
                    } else if val > 0 { return 1 // Clockwise
                    } else { return 2 // Counterclockwise
                    }
                }

                func doIntersect(p1: Point, q1: Point, p2: Point, q2: Point) -> Bool {
                    let o1 = orientation(p: p1, q: q1, r: p2)
                    let o2 = orientation(p: p1, q: q1, r: q2)
                    let o3 = orientation(p: p2, q: q2, r: p1)
                    let o4 = orientation(p: p2, q: q2, r: q1)

                    if o1 != o2 && o3 != o4 {
                        return true
                    }

                    // Collinear cases
                    return false
                }

                // Example
                let p1 = Point(x: 1, y: 1)
                let q1 = Point(x: 10, y: 1)
                let p2 = Point(x: 1, y: 2)
                let q2 = Point(x: 10, y: 2)

                if doIntersect(p1: p1, q1: q1, p2: p2, q2: q2) {
                    print("They intersect.")
                } else {
                    print("They do not intersect.")
                }
                
            

The above code determines whether the given two segments intersect and outputs the results. The method used is to calculate the direction using the orientation function and check for intersection in the doIntersect function.

Optimization of the Algorithm

Below are optimization techniques to confirm the intersection of line segments:

  • Implement a relatively simple linear search algorithm to quickly determine intersection
  • Add additional logic to handle cases where points coincide with the endpoints of segments
  • Use sorted points to improve numerical efficiency in most cases

Conclusion

In this tutorial, we solved an algorithmic problem of determining the intersection of line segments using Swift. The line intersection problem can be useful in various situations and contributes to improving problem-solving skills in algorithms. In actual interviews, you may often encounter similar problems. Therefore, it is important to practice different strategies through such problems.

In the next post, we will cover an algorithm problem on a different topic. Your attention is greatly appreciated!

If you found this post helpful, please leave a comment and share it. If you want more tutorials, please subscribe!

Swift Coding Test Course, Grouping Line Segments

In this course, we will solve one problem to prepare for coding tests using the Swift language. The topic is to divide line segments into groups. We will understand the problem and explain the solution through the following procedures.

Problem Description

The problem is to determine the minimum number of groups into which the given line segments can be divided when there are overlaps. Line segments are expressed by their starting and ending coordinates, and overlapping segments should be grouped together. Each line segment is given in the form [start, end]. For example, it can be given as [1, 3], [2, 5], [6, 8], etc.

Input Format

Multiple line segments are received in the form of an array. For example:

let segments = [[1, 3], [2, 5], [6, 8], [7, 9]]

Output Format

The minimum number of groups needed to divide the segments will be printed. In the above example, it will be 2. ([1, 3] and [2, 5] overlap and belong to the same group, while [6, 8] and [7, 9] are in different groups.)

Solution

To solve the problem, we first need to sort the segments and then group together the overlapping segments. The strategy to solve this problem is as follows:

  1. Sort the segments in ascending order based on their starting points.
  2. Iterate through the sorted segments and check if they overlap with the last segment of the current group.
  3. If they overlap, include them in the same group; if not, create a new group.

Implementation

Now let’s write code in Swift according to the above strategy:

func countGroups(segments: [[Int]]) -> Int {
    guard !segments.isEmpty else { return 0 }
    
    // 1. Sort segments
    let sortedSegments = segments.sorted { $0[0] < $1[0] }
    
    var groups = 1
    var lastEnd = sortedSegments[0][1]

    // 2. Explore segments
    for i in 1..

Code Explanation

The countGroups function takes an array of line segments as input and returns the minimum number of groups. Each step is as follows:

  1. If the array is empty, return 0 for the number of groups.
  2. Sort the input segments based on their starting points.
  3. Set the initial value for the last endpoint as the endpoint of the first segment. Initialize the number of groups to 1.
  4. Iterate through the remaining segments and check if the starting point of the current segment is less than or equal to the endpoint of the last segment to check for overlaps.
  5. If they overlap, update the last endpoint; otherwise, start a new group and increase the number of groups.

Time Complexity Analysis

The time complexity of this algorithm is O(n log n). Sorting the segments takes O(n log n), and iterating through the segments to calculate the groups takes an additional O(n). Therefore, the final time complexity is O(n log n).

Key Points

  • It is important to accurately verify whether the segments overlap.
  • You need to understand how to effectively handle the segments after sorting.

Through this course, I hope you can improve your algorithm problem-solving skills using Swift. The problem and approach above will be useful for preparing for coding tests. I encourage you to practice with additional problems and have opportunities to learn various algorithms!

Swift Coding Test Course, Finding the Direction of Line Segments

Problem Definition

The problem is to determine the direction of line segment AB given two points A(x1, y1) and B(x2, y2). The direction of the line segment reflects how the x-axis and y-axis change as it goes from A to B. We need to determine whether the direction of AB is upward, downward, leftward, or rightward.

The problem is as follows:

Given four integers x1, y1, x2, y2, determine the direction of line segment AB.

  • 0: Horizontal line (y1 == y2)
  • 1: Upward (y1 < y2)
  • -1: Downward (y1 > y2)
  • 2: Rightward (x1 < x2)
  • -2: Leftward (x1 > x2)

Problem Analysis

To find the direction from point A to point B, we need to compare the x-coordinates and y-coordinates of the two points. The following cases are considered.

  • If the y-coordinates are the same, the line segment is considered horizontal (y1 == y2).
  • If A’s y-coordinate is less than B’s y-coordinate, the line segment is directed upward (y1 < y2).
  • If A’s y-coordinate is greater than B’s y-coordinate, the line segment is directed downward (y1 > y2).
  • If A’s x-coordinate is less than B’s x-coordinate, the line segment is directed rightward (x1 < x2).
  • If A’s x-coordinate is greater than B’s x-coordinate, the line segment is directed leftward (x1 > x2).

These conditions can be used to resolve the problem.

Algorithm Design

To solve the problem, we design the following algorithm:

  1. Input the coordinates of two points A(x1, y1) and B(x2, y2).
  2. Compare y1 and y2 to determine the result in three cases (horizontal, upward, downward).
  3. Compare x1 and x2 to define the cases for rightward or leftward directions.
  4. Output the result.

Implementation

Below is the code implemented in Swift based on the above algorithm:

            
                import Foundation
                
                func determineDirection(x1: Int, y1: Int, x2: Int, y2: Int) -> String {
                    if y1 == y2 {
                        return "Horizontal line"
                    } else if y1 < y2 {
                        return "Upward"
                    } else {
                        return "Downward"
                    }
                }
                
                func determineHorizontalDirection(x1: Int, x2: Int) -> String {
                    if x1 < x2 {
                        return "Rightward"
                    } else if x1 > x2 {
                        return "Leftward"
                    } else {
                        return "Vertical line"
                    }
                }
                
                let x1 = 1, y1 = 2, x2 = 3, y2 = 4
                print(determineDirection(x1: x1, y1: y1, x2: x2, y2: y2))
                print(determineHorizontalDirection(x1: x1, x2: x2))
            
            

In the above Swift code, two functions are used to determine the direction of the line segment. The first function determineDirection assesses the direction based on the y-coordinates, while the second function determineHorizontalDirection assesses it based on the x-coordinates. Each case returns the appropriate string.

Test Cases

Now let’s look at a few test cases:

  • Case 1: Line segment from A(1, 2) to B(3, 4)
  • Case 2: Horizontal line from A(1, 3) to B(1, 3)
  • Case 3: Line segment from A(5, 6) to B(2, 5)

We validate the algorithm through the results of each test case:

            
                // Case 1: A(1, 2), B(3, 4)
                let x1_case1 = 1, y1_case1 = 2, x2_case1 = 3, y2_case1 = 4
                print(determineDirection(x1: x1_case1, y1: y1_case1, x2: x2_case1, y2: y2_case1)) // Upward
                print(determineHorizontalDirection(x1: x1_case1, x2: x2_case1)) // Rightward
                
                // Case 2: A(1, 3), B(1, 3)
                let x1_case2 = 1, y1_case2 = 3, x2_case2 = 1, y2_case2 = 3
                print(determineDirection(x1: x1_case2, y1: y1_case2, x2: x2_case2, y2: y2_case2)) // Horizontal line
                print(determineHorizontalDirection(x1: x1_case2, x2: x2_case2)) // Vertical line
                
                // Case 3: A(5, 6), B(2, 5)
                let x1_case3 = 5, y1_case3 = 6, x2_case3 = 2, y2_case3 = 5
                print(determineDirection(x1: x1_case3, y1: y1_case3, x2: x2_case3, y2: y2_case3)) // Downward
                print(determineHorizontalDirection(x1: x1_case3, x2: x2_case3)) // Leftward
            
            

Conclusion

In this post, we examined the process of designing and implementing an algorithm to determine the direction of a line segment given two points. This algorithm allows for a straightforward determination of directionality through the comparison of the given two coordinates.

The problem of determining line segment direction requires a basic geometric approach, and it is important to clearly understand each condition and write the corresponding logic. Through such problems, one can develop algorithmic thinking and improve their skills.