Swift Coding Test Course, I Will Become the President of the Women’s Association

Hello, everyone! In this post, we will address one of the algorithm problems called “I Will Be the Apartment Leader”.
This problem is one of the frequently asked topics in Swift coding tests.
I will explain the basic problem description, the process of solving it, and how to implement the code in detail.

Problem Description

The “I Will Be the Apartment Leader” problem is about calculating the number of residents in an apartment according to specific rules.
The given apartment consists of N floors and K units.
The number of residents in each unit on the K-th floor follows these rules:

  • On the 0-th floor, there is 1 resident in every K unit.
  • The number of residents in unit n on the k-th floor is the sum of the number of residents from unit 1 to n on the (k-1)-th floor.

In other words, the number of residents on the 0-th floor is 1 for everyone, and the number of residents in unit n on the 1st floor is the total from unit 1 to n on the 0-th floor.
We can use these rules to calculate the number of residents in unit n on the k-th floor.

Input and Output Format

Input

  • The first line contains the number of test cases T. (1 ≤ T ≤ 100)
  • Each test case consists of two integers K and N. (0 ≤ K ≤ 14, 1 ≤ N ≤ 14)

Output

  • For each test case, print the number of residents in unit N on the k-th floor.

Process of Solving the Problem

To solve this problem, we first declare a 2-dimensional array to calculate the number of residents in the apartment.
The size of the array is set to (15 x 15) to store the number of residents from the 0-th floor to the 14-th floor.
We will use this to solve the problem using Dynamic Programming.

Step 1: Initialize the Array


let maxK = 15
let maxN = 15
var dp = Array(repeating: Array(repeating: 0, count: maxN), count: maxK)

for i in 0..

Here, dp[k][n] represents the number of residents in unit n on the k-th floor.
We initialized all values on the 0-th floor to 1. For k > 0, we can calculate dp[k][n] as the sum of residents from the previous floor.

Step 2: Calculate the Number of Residents


for k in 1..

This is the process of filling the dp array with values.
The number of residents in unit n on the k-th floor is the sum from units 1 to n on the (k-1)-th floor.
We calculate the values for each floor and store them in the dp array through a loop.

Step 3: Print the Results


for _ in 0..

Finally, we print the number of residents in unit N on the k-th floor for each test case.
Through this process, we can solve the problem.

Implementation Code

Now, the full code that implements the above process in Swift is below.


import Foundation

let maxK = 15
let maxN = 15
var dp = Array(repeating: Array(repeating: 0, count: maxN), count: maxK)

for i in 0..

Conclusion

In this article, we examined the process of solving the "I Will Be the Apartment Leader" problem.
We learned how to understand the rules of the problem and efficiently calculate the solution using Dynamic Programming.
I hope this helps you solidify your understanding of algorithms and prepare for coding tests.
Thank you!

Swift Coding Test Course, Merge Sort

Hello. Today, we will learn about the Merge Sort algorithm implemented in Swift. This tutorial will start from the basics of Merge Sort and explain its application in actual coding tests in detail.

What is Merge Sort?

Merge Sort is a sorting algorithm based on the divide and conquer strategy. It divides the array into two halves, sorts each sub-array, and then merges the two sorted sub-arrays into one sorted array. Merge Sort has an average and worst-case time complexity of O(n log n) and is a stable sort.

Principle of Merge Sort

The process of Merge Sort is as follows:

  1. Given the original array, it is split into two sub-arrays at the midpoint.
  2. Merge Sort is recursively performed on each sub-array.
  3. The two sorted sub-arrays are merged to create one sorted array.

The important point here is that the sub-arrays are sorted at each step. The entire array is sorted by merging these sorted arrays back together.

Problem: Sort Integers

Write a function in Swift that sorts a given list of integers in ascending order. An example input is as follows:


            let nums = [38, 27, 43, 3, 9, 82, 10]
        

To solve this problem, you need to apply the principles of Merge Sort explained above.

Implementing Merge Sort

Now, let’s implement Merge Sort in Swift. Below is the complete code:


            func mergeSort(_ array: [Int]) -> [Int] {
                // 1. If the size of the array is less than 1, return the original array
                if array.count < 2 {
                    return array
                }
                
                // 2. Split the array at the midpoint
                let midIndex = array.count / 2
                let leftArray = mergeSort(Array(array[0.. [Int] {
                var mergedArray: [Int] = []
                var leftIndex = 0
                var rightIndex = 0
                
                // 4. Merge by comparing the two arrays
                while leftIndex < left.count && rightIndex < right.count {
                    if left[leftIndex] < right[rightIndex] {
                        mergedArray.append(left[leftIndex])
                        leftIndex += 1
                    } else {
                        mergedArray.append(right[rightIndex])
                        rightIndex += 1
                    }
                }
                
                // 5. Add remaining elements
                while leftIndex < left.count {
                    mergedArray.append(left[leftIndex])
                    leftIndex += 1
                }
                
                while rightIndex < right.count {
                    mergedArray.append(right[rightIndex])
                    rightIndex += 1
                }
                
                return mergedArray
            }

            // Main
            let nums = [38, 27, 43, 3, 9, 82, 10]
            let sortedNums = mergeSort(nums)
            print(sortedNums) // Result: [3, 9, 10, 27, 38, 43, 82]
        

The above code sorts the input list of numbers using Merge Sort and prints the result. Comments are added at each step to aid understanding.

Code Explanation

Let's take a look at the code line by line:

  1. if array.count < 2 { return array }: If the size of the array is less than 1, it is already sorted, so it is returned as is.
  2. let midIndex = array.count / 2: Calculates the midpoint index of the array.
  3. let leftArray = mergeSort(Array(array[0..: Recursively sorts the left sub-array.
  4. let rightArray = mergeSort(Array(array[midIndex..: Recursively sorts the right sub-array.
  5. return merge(leftArray, rightArray): Merges the sorted left and right arrays and returns the result.

In the merge function, indices are tracked as the two arrays are compared and merged. If one array is exhausted, the remaining elements are added to produce the final result.

Advantages and Disadvantages of Merge Sort

Merge Sort has the following advantages and disadvantages:

Advantages:

  1. Stable sorting: The relative order of elements with equal values is preserved.
  2. Time complexity of O(n log n): It provides a relatively fast sorting performance proportional to the amount of data.
  3. Can be applied to linked lists as well as arrays of fixed size: It can be used in structures that utilize pointers.

Disadvantages:

  1. Requires additional memory: Because a new array is created during the merging process, the space complexity is O(n).
  2. In simpler cases (e.g., nearly sorted cases), simpler algorithms like insertion sort may perform better.

Additional Problems for Skill Improvement

Now that you understand Merge Sort, practice further with these additional problems:

  1. Write a function that takes an array of integers and returns a sorted array with duplicates removed.
  2. Implement an algorithm that finds the index of an element with a specific value in a sorted array using binary search.
  3. Write a function in Swift that merges multiple input arrays into one sorted array.

This concludes our discussion on implementing Merge Sort in Swift. It is important to solidify your understanding of basic data structures and algorithm theories when solving algorithm problems. We will meet again in the next tutorial with more in-depth content. Thank you!

Swift Coding Test Course, Bellman-Ford

Hello! In this course, we will discuss the Bellman-Ford algorithm using Swift. The Bellman-Ford algorithm is designed to find the shortest path from a single source to all vertices in a graph, and it has the advantage of being usable in graphs with negative edge weights. In this lecture, we will explain the concept of the Bellman-Ford algorithm and examine the specific implementation process of the algorithm.

1. Overview of the Bellman-Ford Algorithm

The Bellman-Ford algorithm was developed by Richard Bellman and Lester Ford in 1958. The algorithm operates in the following manner:

  • Updates the initialized distance array for all edges in the graph.
  • Performs relaxation of edges up to the maximum number of vertices – 1 to optimize the distance information.
  • Adds a negative cycle check to verify if a negative cycle exists.

1.1. Algorithm Procedure

  1. Set the initial distance to infinity and initialize the starting vertex’s distance to 0.
  2. Perform relaxation for all edges up to a maximum of V-1 times.
  3. Finally, check for negative cycles on all edges.

2. Defining the Problem

Now let’s define a problem where the Bellman-Ford algorithm can be used.

Problem: Finding the Shortest Path

Given the number of vertices in the graph V, the number of edges E, and the information of the edges, find the shortest path from the starting vertex to all other vertices. If the graph contains a negative cycle, output “Negative Cycle”.

Input Format

V (number of vertices)
E (number of edges)
Edge information (starting vertex, ending vertex, weight)

Output Format

Shortest distance to each vertex or "Negative Cycle"

3. Implementation of the Bellman-Ford Algorithm

Now that we have defined the problem, let’s implement the algorithm using Swift.

import Foundation

struct Edge {
    let from: Int
    let to: Int
    let weight: Int
}

func bellmanFord(vertices: Int, edges: [Edge], start: Int) -> [Int] {
    var distances = Array(repeating: Int.max, count: vertices)
    distances[start] = 0

    // Relaxation phase
    for _ in 0..

3.1. Example Usage

Now let's test the above algorithm using a graph with multiple edges and vertices.

let edges = [
    Edge(from: 0, to: 1, weight: 4),
    Edge(from: 0, to: 2, weight: 1),
    Edge(from: 2, to: 1, weight: 2),
    Edge(from: 1, to: 3, weight: 1),
    Edge(from: 2, to: 3, weight: 5)
]

let result = bellmanFord(vertices: 4, edges: edges, start: 0)
if !result.isEmpty {
    for (index, distance) in result.enumerated() {
        print("Vertex \(index): \(distance)")
    }
}

4. Time Complexity of the Algorithm

The Bellman-Ford algorithm has a time complexity of O(VE) in the worst case, where there are V vertices and E edges. As a result, it can be efficiently used on relatively small graphs, but it may take a long time when the number of edges increases.

5. Conclusion

In this lecture, we covered the basic concept of the Bellman-Ford algorithm, defined the problem using it, implemented the algorithm, and explored an example. We learned that the Bellman-Ford algorithm is a valuable algorithm that can find the shortest path even in graphs with negative weight. I encourage you to use this algorithm to solve various problems.

In the next session, we will cover Dijkstra's algorithm. Thank you!

Swift Coding Test Course, Bubble Sort

1. Problem Definition

Write a function to sort a given integer array in ascending order.
You must implement it using the bubble sort algorithm, which is the most basic sorting method,
and include the process of optimizing the code considering time complexity and space complexity.

Problem: Given an arbitrary integer array, write a Swift function that uses
the bubble sort algorithm to sort this array in ascending order.

2. Overview of Bubble Sort Algorithm

Bubble sort is a simple sorting algorithm that works by comparing two adjacent elements and
swapping them if they are not in the correct order. This process is repeated for all indices of the array,
and in the worst case, it has a time complexity of O(n²) when the size of the array is n.
The main characteristics of bubble sort are as follows:

  • Simple and easy to understand algorithm
  • Usually easy to implement and useful for small datasets
  • Worst case O(n²), average O(n²), best case O(n) (when already sorted)

3. Algorithm Steps

The basic method of using bubble sort is as follows:

  1. Start by comparing adjacent elements from the first element of the array.
  2. If the first element is greater than the second element, swap the two elements.
  3. Repeat this process until the end of the array.
  4. When you reach the end of the array, the largest element will move to the end of the array.
  5. Repeat the above steps n-1 times.

This process ensures that the largest element moves towards the end at each step.

Bubble Sort Implementation (Swift Code)


func bubbleSort(_ array: inout [Int]) {
    let n = array.count
    for i in 0.. array[j+1] {
                // Swap
                let temp = array[j]
                array[j] = array[j+1]
                array[j+1] = temp
                swapped = true
            }
        }
        // If no two elements were swapped by inner loop, then break
        if !swapped {
            break
        }
    }
}
    

4. Code Explanation

The above bubbleSort function takes an array as an argument and sorts it in ascending order.
Key Points:

  • inout keyword allows the function to modify the array directly.
  • The reason for using n-i-1 in the second for loop is that with each iteration the largest element moves to the end of the array.
    Therefore, the last element is already sorted and does not need to be checked.
  • The swapped variable checks if the sorting is already completed to reduce unnecessary iterations.

5. Testing and Example

Below is an example that tests the bubbleSort function.


var myArray = [64, 34, 25, 12, 22, 11, 90]
print("Before sorting: \(myArray)")

bubbleSort(&myArray)

print("After sorting: \(myArray)")
    

Running the above code will display the array before and after sorting.
This will confirm that the bubble sort algorithm has been implemented successfully.

6. Time Complexity and Optimization

The time complexity of bubble sort is O(n²) in the worst case.
Even when the array is already sorted, it can perform at O(n) in the best case.
To optimize this, the swapped variable can be introduced to avoid unnecessary iterations.

In Swift, using bubble sort for large arrays is inefficient.
In this case, it is recommended to use advanced sorting algorithms (e.g., Quick Sort, Merge Sort).

7. Conclusion

In this tutorial, we explored how to implement the bubble sort algorithm in Swift and its process.
Bubble sort is easy to understand and simple to implement, but its performance may degrade in real usage.
Therefore, when dealing with complex datasets, other algorithms should be considered.
In the next tutorial, we will cover the more efficient sorting algorithm called Quick Sort.

8. References

For a deeper understanding of the algorithm, please refer to the materials below:

Swift Coding Test Course, Bubble Sort Program 2

Hello! In this course, we will delve deeper into algorithms for preparing coding tests using Swift, specifically focusing on Bubble Sort. The problem we will solve is sorting an array, and we will implement this using the Bubble Sort algorithm. This course will include the following topics:

  • Explanation of the principles and workings of Bubble Sort
  • Implementation of the code in Swift
  • Examples of code execution
  • Suggestions for optimization and improvement
  • Analysis of the time complexity of Bubble Sort

1. What is Bubble Sort?

Bubble Sort is a very simple and intuitive sorting algorithm. It works by comparing two adjacent elements in an array and sorting them in order. This process can be visualized as the largest value “bubbling” up to the end of the array.

The Working Principle of Bubble Sort

  1. Start from the beginning of the array and compare two adjacent elements.
  2. If the first element is greater than the second, swap the two elements.
  3. Repeat this process until the end of the array.
  4. After completing one pass, the largest value moves to the end of the array.
  5. Repeat this process until the last element remains sorted.

2. Problem Definition

Given an integer array, sort this array in ascending order using Bubble Sort.

Input: [64, 34, 25, 12, 22, 11, 90]
Output: [11, 12, 22, 25, 34, 64, 90]

3. Implementation of Swift Code

Now, let’s write the code to solve this problem using Swift.

func bubbleSort(arr: [Int]) -> [Int] {
    var sortedArray = arr
    let n = sortedArray.count
    
    for i in 0.. sortedArray[j+1] {
                // Swap
                let temp = sortedArray[j]
                sortedArray[j] = sortedArray[j+1]
                sortedArray[j+1] = temp
            }
        }
    }
    return sortedArray
}

// Example execution
let array = [64, 34, 25, 12, 22, 11, 90]
let sortedArray = bubbleSort(arr: array)
print(sortedArray)  // Output: [11, 12, 22, 25, 34, 64, 90]

4. Code Execution Example

When we execute the above Swift code, the given array is successfully sorted. In this code, we use two nested for loops to compare all the elements of the array. This can be time-consuming, but the true advantage of Bubble Sort is its intuitive nature.

5. Optimization and Improvement Methods

Bubble Sort has a time complexity of O(n^2), which is inefficient. However, a few simple optimization techniques can be applied:

  • Early termination: If no swaps occur during a pass, the array is already sorted, so no further comparisons are necessary.
  • Reducing the range of comparisons: Elements at both ends that have already been passed don’t need to be compared in subsequent passes.

The code with these optimizations can be modified as follows:

func optimizedBubbleSort(arr: [Int]) -> [Int] {
    var sortedArray = arr
    let n = sortedArray.count
    var swapped: Bool
    
    for i in 0.. sortedArray[j+1] {
                // Swap
                let temp = sortedArray[j]
                sortedArray[j] = sortedArray[j+1]
                sortedArray[j+1] = temp
                swapped = true
            }
        }
        // If no swaps occurred, sorting is complete, so exit
        if !swapped {
            break
        }
    }
    return sortedArray
}

6. Time Complexity of Bubble Sort

The time complexity of Bubble Sort is O(n^2) in both average and worst-case scenarios. The best case (when the array is already sorted) can be O(n), making it more efficient. For this reason, Bubble Sort may be effective on small data sets, but in real applications, it is common to use more efficient sorting algorithms.

Conclusion

In this course, we had the opportunity to implement Bubble Sort using Swift and learn the basics of algorithm sorting. By solving basic problems like sorting an array, we were able to understand the workings and time complexity of algorithms. In the next course, we will cover a more efficient sorting algorithm called Quick Sort. Thank you for being with us!