Swift Coding Test Course, Exploring Dynamic Programming

Dynamic Programming (DP) is one of the algorithm design techniques that solves complex problems by breaking them down into simpler subproblems.
In this article, we will learn how to apply dynamic programming using the Swift language and have the opportunity to practice the theory through real algorithm problems.

Basics of Dynamic Programming

Dynamic programming is a method of solving a given problem by dividing it according to optimal substructure.
There are fundamentally two main elements: Memoization and Tabulation.
Memoization is a way to store the results of solved problems recursively to avoid redundant calculations,
while Tabulation involves storing the results of subproblems in a table to solve the problem in a bottom-up manner.

Problem Introduction: Fibonacci Sequence

The Fibonacci sequence is a sequence of natural numbers where the first two terms are 0 and 1,
and the subsequent terms are defined as the sum of the two preceding terms.
That is, F(0) = 0, F(1) = 1, F(n) = F(n-1) + F(n-2) (n >= 2).

Let’s understand the concept of dynamic programming while implementing an efficient way to calculate the Fibonacci sequence.

Problem Solving Process

1. Understanding the Problem

This is a problem to find the nth term of the Fibonacci sequence.
There is a simple definition, but if implemented with a recursive method, redundant calculations occur, making it inefficient.

2. Applying Dynamic Programming

By using dynamic programming, we can avoid redundant calculations.
In particular, by storing and reusing previously computed results from subproblems, we can reduce the time complexity.
Here, we will solve the problem using the memoization approach.

3. Implementing Memoization

Memoization is a way of saving previously computed results by using additional variables in the recursive function.
Let’s write the code in Swift.

            
                func fibonacci(_ n: Int, _ memo: inout [Int?]) -> Int {
                    if let value = memo[n] {
                        return value
                    }
                    if n <= 1 {
                        memo[n] = n
                        return n
                    }
                    memo[n] = fibonacci(n - 1, &memo) + fibonacci(n - 2, &memo)
                    return memo[n]!
                }
                
                func fibonacciWrapper(n: Int) -> Int {
                    var memo = Array(repeating: nil, count: n + 1)
                    return fibonacci(n, &memo)
                }
                
                // Example call
                let result = fibonacciWrapper(n: 10)
                print(result) // Output: 55
            
        

4. Analyzing Time Complexity

The time complexity of the Fibonacci sequence using memoization is O(n).
It demonstrates efficient performance because it computes each n only once and stores the results.
The space complexity is also O(n).

5. Implementing Using Tabulation Method

Now, let’s solve the same problem using the tabulation method.
This method approaches the problem in a bottom-up manner by storing the results of subproblems in a table.
Let’s write the code in Swift.

            
                func fibonacciTabulation(_ n: Int) -> Int {
                    if n <= 1 { return n }
                    var dp = Array(repeating: 0, count: n + 1)
                    dp[0] = 0
                    dp[1] = 1
                    
                    for i in 2...n {
                        dp[i] = dp[i - 1] + dp[i - 2]
                    }
                    return dp[n]
                }
                
                // Example call
                let resultTabulation = fibonacciTabulation(n: 10)
                print(resultTabulation) // Output: 55
            
        

6. Conclusion

In this article, we learned the basic concepts of dynamic programming using Swift and practiced the memoization and tabulation techniques through the Fibonacci sequence problem.
Dynamic programming is a powerful tool that can be applied to various algorithmic problems,
and understanding and applying the theory will greatly help in coding tests as well.

I hope this course provides a deep understanding and practice of dynamic programming.

We will return with more diverse topics in the future. Thank you!

Swift Coding Test Course, Dijkstra

Today, we will solve the problem of finding the shortest path using Dijkstra’s algorithm in Swift. The Dijkstra algorithm is one of the most important algorithms in graph theory and is used to find the shortest path from a specific node to all other nodes.

Introduction to the Algorithm

Dijkstra’s Algorithm is a graph search algorithm developed by computer scientist Edgar Dijkstra in 1956. This algorithm is effective for finding the shortest path in graphs without negative weights.

How It Works

The algorithm proceeds in the following steps:

  1. Select the starting node and set the distance of this node to 0.
  2. Update the distances to neighboring nodes.
  3. After calculating the distances to all nodes, select the closest node and move to the next node.
  4. Repeat this process until you find the shortest distance to all nodes.

Example Problem

Here is a problem that can be solved using Dijkstra’s algorithm:

Problem: Find the Shortest Path

Given a graph, find the shortest path from a specific starting node to other nodes. Below is the weighted adjacency list of the graph:

0: {1: 4, 2: 1}
1: {2: 2, 3: 5}
2: {1: 1, 3: 8}
3: {}

For the above graph, write a program to find the shortest path from node 0 to node 3. The result should be able to find the shortest path as 0 -> 2 -> 1 -> 3.

Swift Implementation

Now, let’s implement Dijkstra’s algorithm in Swift to solve the above problem.


import Foundation

// Class to represent the graph
class Graph {
    var vertices: Int
    var adjList: [[(node: Int, weight: Int)]]
    
    init(vertices: Int) {
        self.vertices = vertices
        self.adjList = Array(repeating: [], count: vertices)
    }

    func addEdge(source: Int, destination: Int, weight: Int) {
        adjList[source].append((node: destination, weight: weight))
    }

    func dijkstra(source: Int) -> [Int] {
        var distances = Array(repeating: Int.max, count: vertices)
        var visited = Array(repeating: false, count: vertices)
        distances[source] = 0

        for _ in 0.. Int {
        var min = Int.max
        var minIndex = -1
        
        for v in 0..

In the above code, the graph class uses an adjacency list to store relationships between nodes and calculates the shortest path using Dijkstra's algorithm. It outputs the shortest path from node 0 to node 3 for the given example.

Conclusion

Dijkstra's algorithm is a very useful tool for solving the shortest path problem. By implementing it in Swift, you can understand how the algorithm works and enhance your important coding skills through practical programming exercises. I encourage you to use Dijkstra's algorithm to solve various graph problems.

If you want to learn more about algorithms and solutions, please continue to follow my blog!

Swift Coding Test Course, Bridge Building

Hello! Today, I would like to talk about how to prepare for coding tests using Swift. In this tutorial, we will cover the algorithmic problem called Bridge Building. This problem can be solved using the concepts of combination and dynamic programming.

Problem Description

The Bridge Building problem assumes the following situation: there is a piece of land that is N units wide. On both sides of the land, pillars numbered from 1 to N are erected. Given a fixed number of pillars and bridges, the goal is to calculate the number of ways to place bridges between two pillars.

Since the bridges cannot cross each other, the ways of placing the bridges must not overlap. In other words, to place a bridge between pillar A and pillar B, A must be before B. The problem is to take the number of pillars N as input and output the number of possible ways to place bridges.

Problem Input

  • Input: Integer N (1 ≤ N ≤ 30)

Problem Output

  • Output: The number of possible ways to place bridges

Problem Solving Process

To solve this problem, the following steps are taken:

1. Understanding Combinations

This problem can be reduced to a combination problem. When there are N pillars, the number of ways to place bridges among the N pillars is defined as the number of combinations of choosing 2 from N pillars. Mathematically, this can be expressed as:

C(N, 2) = N! / (2! * (N - 2)!)

However, this problem is not a simple combination problem; it also considers the order and overlap of the bridges placed between the pillars.

2. Dynamic Programming Approach

This problem can be approached using dynamic programming. We define dp[i] as the number of ways to place bridges when there are i pillars. The state transition equation is defined as follows:

dp[i] = dp[i-1] + dp[i-2] * (i - 1)

This equation is based on the following ideas:

  • When not placing a bridge among i-1 pillars: This case is represented by dp[i-1].
  • When placing one bridge: This case is expressed as dp[i-2] * (i - 1). After placing a bridge between two pillars, i-2 pillars remain.

3. Setting Initial Conditions

Now we need to establish the initial conditions. We can set dp[1] = 1 and dp[2] = 1. When there is only one pillar, no bridge can be placed, and when there are two pillars, only one bridge can be placed.

4. Implementing in Swift

import Foundation

func bridgeCombinations(n: Int) -> Int {
    var dp = [0] * (n + 1)
    dp[1] = 1
    if n > 1 {
        dp[2] = 1
    }
    
    for i in 3...n {
        dp[i] = dp[i - 1] + dp[i - 2] * (i - 1)
    }
    
    return dp[n]
}

// Testing the Bridge Building Problem
let n = 5 // Set the desired N value here.
let result = bridgeCombinations(n: n)
print("Number of ways to place bridges: \(result)")

The code above implements a solution for the Bridge Building problem. It outputs the result based on the n value. This is an example solved using dynamic programming with Swift arrays.

Conclusion

We learned how to solve the Bridge Building algorithm problem using Swift. Understanding how dynamic programming and combinations combine is essential, especially in similar problems. You may often encounter such problems in actual coding tests, so don’t forget to practice!

I hope this post has been helpful for your coding test preparation. I will return with more posts covering various algorithms and coding problems.

Swift Coding Test Course, Calculating the Area of a Polygon

1. Problem Definition

In this session, we will handle the problem of calculating the area of a given polygon. When the vertices of the polygon are provided, we will implement an algorithm to calculate the area using them. The algorithm used for area calculation is based on the Strassen Algorithm.

2. Problem Input

The function has the following shape:

func polygonArea(vertices: [(Double, Double)]) -> Double

Here, vertices is an array of tuples representing each vertex of the polygon. Each tuple contains the x and y coordinates.

3. Algorithm Explanation

To calculate the area of the polygon, we will use the polygon area formula. This formula is as follows:

Area = 0.5 * | Σ (xi * yi+1 - yi * xi+1) |

Here, i represents the index from 0 to n-1, and the last vertex connects to the first vertex. To code this formula, we will follow these steps:

  1. Calculate the number of vertices n.
  2. Calculate the area contribution for each vertex.
  3. Sum all contributions.
  4. Convert the result to absolute value and multiply by 0.5.

4. Code Implementation

Now, let’s implement the above algorithm in Swift. Here is the complete code:

func polygonArea(vertices: [(Double, Double)]) -> Double {
    var area = 0.0
    let n = vertices.count

    for i in 0..

4.1 Code Explanation

The code above works as follows:

  • First, the area variable is initialized to prepare for area calculation.
  • n stores the number of vertices of the polygon.
  • For each vertex i, the next vertex j is calculated (where j is set to (i + 1) % n to connect the last vertex to the first vertex).
  • The area contribution is calculated and accumulated in area.
  • At the end of the loop, the absolute value of the area is divided by 2 to return the result.

5. Test Cases

Now we will validate this function with various test cases. Here are some examples:

let example1 = [(0.0, 0.0), (4.0, 0.0), (4.0, 3.0), (0.0, 4.0)]
let area1 = polygonArea(vertices: example1)
print(area1) // 12.0

let example2 = [(1.0, 1.0), (3.0, 1.0), (3.0, 3.0), (1.0, 3.0)]
let area2 = polygonArea(vertices: example2)
print(area2) // 4.0

let example3 = [(0.0, 0.0), (5.0, 0.0), (5.0, 5.0), (0.0, 5.0)]
let area3 = polygonArea(vertices: example3)
print(area3) // 25.0

6. Conclusion

In this tutorial, we implemented an algorithm in Swift to calculate the area of a polygon. We verified that the algorithm works correctly through various test cases. These types of problems can deepen our understanding of data structures and algorithms, which will be useful in future coding tests.

If more complex problems related to polygons or various types of area calculations are needed, we can consider additional optimizations and expansions based on this algorithm. In the next tutorial, we will cover these advanced techniques.

Swift Coding Test Course, Breadth-First Search

1. Introduction

Breadth-First Search (BFS) is an algorithm for traversing nodes in a graph or tree structure.
BFS explores adjacent nodes first from the starting node, then examines the adjacent nodes of those nodes,
visiting all levels of nodes in order. This method is useful for finding the shortest path since it explores
the graph or tree level by level and can be applied to many problems.

2. Problem Description

Problem: Finding the Shortest Path

The given 2D grid contains three types of elements:

  • 0: Walkable area
  • 1: Obstacle
  • 2: Starting point
  • 3: Destination point

The problem is to find the shortest path from the starting point (2) to the destination (3)
within the grid, and output the minimum number of moves required to travel along that path.
If the destination cannot be reached, output -1.

Input Format

        4 4
        0 0 1 0
        0 1 0 0
        2 0 1 0
        0 0 3 0
        

Output Format

        7
        

In the above example, the minimum number of moves from the starting point to the destination is 7.

3. Problem Analysis

BFS can be used to solve this problem.
BFS is suitable for finding the shortest path, starting from the starting point (2) in the given grid and
exploring the path to the destination (3) by moving to adjacent walkable areas (0).
Possible directions for movement are limited to four: up, down, left, and right.

One of the features of BFS is that it adds each node to the queue, allowing it to search in level order.
This makes it easy to count the number of moves needed to reach a specific node.
This method can be used to explore all 0s and 3s filled in the grid to check whether the destination can be reached.

4. Algorithm Design

1. **Initialize the grid and objects**: Initialize the queue for breadth-first search and a visited array based on the input grid.
2. **Add the starting point to the queue**: Add the starting point to the queue and update the visited array.
3. **Execute BFS**: For each node removed from the queue, check its four neighbors.
If the neighbor is walkable, add it to the queue and mark it as visited.
4. **Check for reaching the destination**: If the destination is reached, output the number of moves at that point.
5. **Handle cases where destination is unreachable**: If the queue is empty but the destination has not been reached, output -1.

5. Code Implementation

Now, we will implement BFS in Swift based on the above algorithm design.


import Foundation

func findShortestPath(grid: [[Int]], start: (Int, Int), end: (Int, Int)) -> Int {
    let directions = [(1, 0), (-1, 0), (0, 1), (0, -1)]
    var queue: [(Int, Int, Int)] = [(start.0, start.1, 0)] // (x, y, distance)
    var visited = grid
    visited[start.0][start.1] = 1 // Mark as visited

    while !queue.isEmpty {
        let (x, y, distance) = queue.removeFirst()
        
        // If reached the destination
        if (x, y) == end {
            return distance
        }

        // Explore neighboring nodes
        for direction in directions {
            let newX = x + direction.0
            let newY = y + direction.1
            
            // If within valid range and walkable
            if newX >= 0, newY >= 0, newX < grid.count, newY < grid[0].count, visited[newX][newY] == 0 {
                queue.append((newX, newY, distance + 1))
                visited[newX][newY] = 1 // Mark as visited
            }
        }
    }
    
    // If destination is not reached
    return -1
}

// Example input
let grid: [[Int]] = [
    [0, 0, 1, 0],
    [0, 1, 0, 0],
    [2, 0, 1, 0],
    [0, 0, 3, 0]
]

if let start = grid.enumerated().flatMap({ $0.element.enumerated().compactMap { $1 == 2 ? ($0.offset, $0.element) : nil } }).first,
   let end = grid.enumerated().flatMap({ $0.element.enumerated().compactMap { $1 == 3 ? ($0.offset, $0.element) : nil } }).first {
    let result = findShortestPath(grid: grid, start: start, end: end)
    print(result) // Output the minimum number of moves
}

6. Code Explanation

The code above finds the starting point and destination in the given grid and then
performs breadth-first search to find the shortest path.

  • The four directions for exploration are defined as up, down, left, and right.
  • A visited array is used to ensure that
    already visited nodes are not added to the queue again.
  • When the destination is reached, the current distance is returned.
  • If the destination cannot be reached, it returns -1.

7. Conclusion

Breadth-First Search (BFS) is a highly useful algorithm for solving shortest path problems.
It works efficiently in structures like 2D grids and frequently appears in various programming challenges.
It is important to practice different types of BFS problems to enhance understanding of the algorithm and problem-solving skills.
Through this tutorial, we hope you have gained a fundamental understanding of BFS and learned how to solve actual problems.

8. Additional Practice Problems

Try your hand at the following variant problems:

  • Reach the destination while avoiding obstacles (1) using only a specific path in the given grid.
  • Finding the shortest paths between multiple starting and ending points.
  • Finding the shortest path when diagonal movements are also allowed, instead of only grid movements.

Tackling these problems will further enhance your understanding of the breadth-first search algorithm and improve your problem-solving abilities.