JavaScript Coding Test Course, Implementing the Euler’s Phi Function

Hello, everyone! Today I will explain in detail how to implement the Euler’s totient function (𝜙(n)) using JavaScript. The Euler’s totient function represents the number of integers less than or equal to a given integer n that are coprime to n. This problem appears very frequently in algorithmic problems related to number theory and can be useful in various coding tests.

What is the Euler’s Totient Function?

The Euler’s totient function 𝜙(n) returns the count of positive integers from 1 to n that are coprime to n. In other words, two numbers a and b are said to be coprime if their greatest common divisor (GCD) is 1.

For example:

  • 𝜙(1) = 1 (The only number coprime to 1 is 1 itself)
  • 𝜙(2) = 1 (The number less than 2 and coprime to 2 is 1)
  • 𝜙(3) = 2 (The numbers less than 3 and coprime to 3 are 1, 2)
  • 𝜙(4) = 2 (The numbers less than 4 and coprime to 4 are 1, 3)
  • 𝜙(5) = 4 (The numbers less than 5 and coprime to 5 are 1, 2, 3, 4)

Problem Definition

Now, let’s define the coding test problem.

Problem: Write a function to calculate the Euler's totient function for a given integer n.
Input: Integer n (1 ≤ n ≤ 106)
Output: The value of the Euler's totient function 𝜙(n)

Problem Solving Approach

There are several methods to calculate the Euler’s totient function. The most efficient method is to modify the Sieve of Eratosthenes to compute 𝜙(n) in one go. The time complexity of this method is O(n log log n).

Properties of the Euler’s Totient Function

The key properties required to calculate 𝜙(n) are as follows:

  • 𝜙(p) = p – 1, where p is a prime number
  • 𝜙(p1 * p2 * … * pk) = p1 * p2 * … * pk * (1 – 1/p1) * (1 – 1/p2) * … * (1 – 1/pk)
  • 𝜙(n) = n * (1 – 1/p1) * (1 – 1/p2) * … * (1 – 1/pk), where pi are the prime factors of n.

JavaScript Code Implementation

Based on the above properties, let’s write the code to implement the Euler’s totient function.


function eulerPhi(n) {
    // Declare and initialize the array
    const phi = Array.from({ length: n + 1 }, (_, i) => i);
    
    // Find primes using Sieve of Eratosthenes
    for (let p = 2; p <= n; p++) {
        if (phi[p] === p) { // If p is prime
            for (let k = p; k <= n; k += p) {
                // Update the value of 𝜙(k)
                phi[k] = Math.floor(phi[k] * (1 - 1 / p));
            }
        }
    }
    
    // Return phi(n) for n
    return phi[n];
}

// Test cases
console.log(eulerPhi(1));  // 1
console.log(eulerPhi(2));  // 1
console.log(eulerPhi(3));  // 2
console.log(eulerPhi(4));  // 2
console.log(eulerPhi(5));  // 4

Code Explanation

The code works as follows:

  1. First, an array phi of size n + 1 is created, and each element is initialized to itself. phi[i] starts with the value of i.
  2. Loop from 2 to n, checking each number p to see if it is prime. If phi[p] equals p, it is considered prime.
  3. If p is prime, find its multiples and update the values of phi[k]. The update is performed as 𝜙(k) = 𝜙(k) * (1 - 1/p).
  4. Finally, return the value of phi[n] to compute the value of the Euler’s totient function for n.

Complexity Analysis

The time complexity of the above code is O(n log log n). This is due to the use of the Sieve of Eratosthenes method. The space complexity is O(n), as it requires space equivalent to the size of n to store the array phi.

Conclusion

We have learned how to implement the Euler's totient function in JavaScript. This method is very useful for algorithm testing and number theory, allowing for efficient computation of the Euler's totient value. Use this code to solve various problems!

Going Further

If you want to practice solving similar problems, working on problems involving the greatest common divisor or least common multiple would also be good practice. Additionally, exploring other concepts in number theory such as primality testing and prime generation is recommended. Enhance your understanding of algorithms through mathematical reasoning!

References

I hope this post was helpful. If you have any questions or additional inquiries, please leave a comment! Thank you!

JavaScript Coding Test Course, Finding Minimum Spanning Tree

Today, we will learn about a method to find the “Minimum Spanning Tree (MST)” which is a common problem in algorithm tests. In particular, we will explain how to solve this problem step by step using JavaScript. Through this tutorial, you will understand all the concepts and develop the ability to confidently solve this problem in actual coding tests.

1. What is a Minimum Spanning Tree?

A Minimum Spanning Tree is a subgraph that includes all vertices of a connected graph and has the minimum sum of edge weights. In other words, it refers to a tree that connects all vertices with the least cost. MST is used in various fields such as network design, transportation systems, and clustering.

2. Problem Description

When given the vertices and edges information of a graph, please write a function that finds the Minimum Spanning Tree and returns its total weight.

Input Format

  • The number of vertices n (1 ≤ n ≤ 1000)
  • The number of edges m (1 ≤ m ≤ 10000)
  • Each edge is given in the form of (a, b, c), where a and b are the vertices and c is the weight of the edge.

Output Format

Print the total weight of the Minimum Spanning Tree.

Example

    Input:
    4 5
    1 2 1
    1 3 4
    2 3 2
    1 4 3
    3 4 5

    Output:
    6
    

3. Algorithm Selection

There are several methods to find the Minimum Spanning Tree. Among these, Kruskal’s Algorithm and Prim’s Algorithm are widely used. We will use Kruskal’s Algorithm here.

Kruskal’s Algorithm

Kruskal’s Algorithm sorts the edges based on their weights and selects the edge with the lowest weight first, ensuring that no cycles are formed so that it can create the Minimum Spanning Tree. This method first sorts the given list of edges and then adds the lightest edges one by one.

4. Algorithm Implementation

Now, let’s write the JavaScript code to solve the problem using Kruskal’s Algorithm. The overall steps are as follows:

  1. After receiving edge information, sort them based on weights.
  2. Use the Union-Find data structure to include edges without forming cycles.
  3. After processing all edges, calculate and return the total weight of the Minimum Spanning Tree.

Code Implementation

    
    function find(parent, i) {
        if (parent[i] === -1) {
            return i;
        }
        return find(parent, parent[i]);
    }

    function union(parent, x, y) {
        const xset = find(parent, x);
        const yset = find(parent, y);
        parent[xset] = yset;
    }

    function kruskal(n, edges) {
        edges.sort((a, b) => a[2] - b[2]); // Sort by edge weight
        let parent = Array(n + 1).fill(-1);
        let minWeight = 0;
        const mst = [];

        for (let i = 0; i < edges.length; i++) {
            const [u, v, weight] = edges[i];

            if (find(parent, u) !== find(parent, v)) {
                union(parent, u, v);
                minWeight += weight;
                mst.push([u, v, weight]);
            }
        }

        return { minWeight, mst };
    }

    // Example input data
    const n = 4;
    const edges = [
        [1, 2, 1],
        [1, 3, 4],
        [2, 3, 2],
        [1, 4, 3],
        [3, 4, 5]
    ];

    const result = kruskal(n, edges);
    console.log("Total weight of the Minimum Spanning Tree:", result.minWeight);
    
    

5. Code Explanation

The above code is a function that uses Kruskal's Algorithm to find the Minimum Spanning Tree of the given graph. It is divided into the following key parts:

5.1. Union-Find Function

The Union-Find data structure is used to track the connected components of the graph. Each node has its own parent. The find function finds the representative of the set that the node belongs to, and the union function merges two sets.

5.2. Edge Sorting

Sort the list of edges by weight to select the minimum weight edge first. The sort method in JavaScript can be used to sort easily.

5.3. Minimum Spanning Tree Construction

For each edge, check the parents of the two nodes and select the edge only if it does not create a cycle. The selected edges are stored in the mst array, and the sum of the weights is incremented in the minWeight variable.

6. Performance Analysis

The time complexity of Kruskal's Algorithm is O(E log E). Here, E is the number of edges. Under the constraints of the given problem, this algorithm is efficient. You can expect additional performance improvements with the path compression technique of Union-Find.

7. Conclusion

In this tutorial, we learned about Kruskal's Algorithm to find the Minimum Spanning Tree using JavaScript and explained in detail how to solve the problem. Graph problems are frequently posed in algorithm competitions and various coding tests, so mastering this content will be very helpful. Next, we will solve various problems using other algorithms or data structures.

8. Practice Problem

Try to solve the following problem. After solving it, review your code to check for any parts that can be optimized.

Write an algorithm to extract the edges of the Minimum Spanning Tree from the given graph and output this list of edge weights.

9. References

JavaScript Coding Test Course, Radix Sort

This course will introduce the Radix Sort algorithm implemented in JavaScript and detail how to use it to solve coding test problems. We will systematically learn the concept of the Radix Sort algorithm, its implementation method, time complexity, and example problems.

What is Radix Sort?

Radix Sort is one of the sorting algorithms and an efficient method for sorting numbers with a similar number of digits. The key to this method is to sort the numbers by dividing them into individual digits (units, tens, etc.) and then sequentially considering the digits to sort the entire number.

The Principle of Radix Sort

Radix Sort proceeds in the following order:

  1. Find the maximum number of digits in the input array. This determines how many passes are needed to perform the sorting.
  2. Perform a stable sort for each digit, starting from the least significant digit (units) to the most significant digit (maximum digit).
  3. Finally, after all digit sorting is complete, the original array will be sorted.

Time Complexity

The time complexity of Radix Sort mainly depends on the stable sorting algorithm used, but it is generally O(nk), where n is the number of numbers to be sorted and k is the digit length of the largest number. Radix Sort can only be used for integers by nature, but it can also be applied in a modified version for characters or strings.

Implementing Radix Sort in JavaScript

Basic Algorithm Implementation

Below is an example code of Radix Sort implemented in JavaScript:

function getMax(array) {
    let max = array[0];
    for (let i = 1; i < array.length; i++) {
        if (array[i] > max) {
            max = array[i];
        }
    }
    return max;
}

function countingSort(array, place) {
    const n = array.length;
    const output = new Array(n);
    const count = new Array(10).fill(0);

    for (let i = 0; i < n; i++) {
        const digit = Math.floor(array[i] / place) % 10;
        count[digit]++;
    }

    for (let i = 1; i < 10; i++) {
        count[i] += count[i - 1];
    }

    for (let i = n - 1; i >= 0; i--) {
        const digit = Math.floor(array[i] / place) % 10;
        output[count[digit] - 1] = array[i];
        count[digit]--;
    }

    for (let i = 0; i < n; i++) {
        array[i] = output[i];
    }
}

function radixSort(array) {
    const max = getMax(array);
    for (let place = 1; Math.floor(max / place) > 0; place *= 10) {
        countingSort(array, place);
    }
    return array;
}

// Usage example
const numbers = [170, 45, 75, 90, 802, 24, 2, 66];
console.log(radixSort(numbers)); // Output: [2, 24, 45, 66, 75, 90, 170, 802]

Example Problem: Sorting an Integer Array

Now, let’s apply Radix Sort to a practical problem. The problem is as follows:

Problem: Given an array of integers, write a function to sort this array in ascending order using the Radix Sort algorithm.

Problem Approach

  1. Receive the input array as a function argument.
  2. Use the Radix Sort algorithm to sort the array.
  3. Return the sorted array.

Implementation and Testing

Based on the Radix Sort algorithm explained above, we can implement a function to solve the problem as follows:

function sortIntegers(array) {
    return radixSort(array);
}

// Test
const testArray = [5, 3, 8, 1, 2, 7, 4, 6];
console.log(sortIntegers(testArray)); // Output: [1, 2, 3, 4, 5, 6, 7, 8]

Conclusion

In this course, we learned about the Radix Sort algorithm and how to implement it in JavaScript. Radix Sort is very efficient for sorting large integers, especially showing excellent performance for numbers with fewer digits. Utilizing Radix Sort to approach various coding test problems will be a very beneficial experience. I hope you make good use of the concepts and implementation methods of Radix Sort in your upcoming coding tests.

Javascript Coding Test Course, Representation of Graphs

Graphs are powerful data structures for solving various problems. In this post, we will explore how to represent graphs and explain the problem-solving process in detail.

Definition of Graph

A graph is a data structure composed of vertices and edges, where vertices represent objects or nodes, and edges represent relationships between vertices. Graphs can be divided into directed graphs (Directed Graph) and undirected graphs (Undirected Graph).

Additionally, graphs can be weighted (Weighted Graph) or unweighted (Unweighted Graph). In weighted graphs, costs or distances are assigned to edges.

Ways to Represent Graphs

There are two main ways to represent graphs:

  • Adjacency Matrix: Represent the relationships between vertices using a two-dimensional array. The size of the array is determined by the number of vertices, and the values in the matrix indicate the presence of an edge between two vertices or include weights.
  • Adjacency List: Represent a list of adjacent vertices for each vertex. This method is memory efficient and advantageous for sparse graphs.

Problem: Finding Paths in a Graph

Let’s solve the following problem.

Problem Description: Given a graph with two vertices A and B, write a function to find and print all paths from A to B.

The graph is given as an adjacency list.

Example Problem

Input:
graph = {
    'A': ['B', 'C'],
    'B': ['D'],
    'C': ['D'],
    'D': ['E'],
    'E': []
}
start = 'A'
end = 'E'

Output:
['A', 'B', 'D', 'E']
['A', 'C', 'D', 'E']
            

Problem-Solving Process

To solve this problem, we will use the Depth-First Search (DFS) algorithm. DFS is an algorithm that explores the depth of the graph to find all possible paths.

Step 1: Define the DFS Function

First, we define a DFS function that explores all paths starting from the current vertex. This function maintains the current path as a list and stores the path when it reaches the target vertex.


function findPaths(graph, start, end, path = [], paths = []) {
    path.push(start); // Add the current vertex to the path

    // Save the path if the target vertex is reached
    if (start === end) {
        paths.push([...path]);
    } else {
        // Call DFS for adjacent vertices
        for (const neighbor of graph[start] || []) {
            findPaths(graph, neighbor, end, path, paths);
        }
    }

    path.pop(); // Remove the current vertex from the path (backtracking)
    return paths; // Return all paths
}
            

Step 2: Define the Graph and Input Values

Now, we define the graph along with the starting and ending vertices.


const graph = {
    'A': ['B', 'C'],
    'B': ['D'],
    'C': ['D'],
    'D': ['E'],
    'E': []
};

const start = 'A';
const end = 'E';
            

Step 3: Execute the Function

We will execute the function to find all paths and print the results.


const allPaths = findPaths(graph, start, end);
console.log(allPaths);
            

Final Code


function findPaths(graph, start, end, path = [], paths = []) {
    path.push(start); // Add the current vertex to the path
    if (start === end) {
        paths.push([...path]); // Add the path when it is complete
    } else {
        for (const neighbor of graph[start] || []) {
            findPaths(graph, neighbor, end, path, paths); // Call DFS
        }
    }
    path.pop(); // Backtracking
    return paths; // Return all paths
}

const graph = {
    'A': ['B', 'C'],
    'B': ['D'],
    'C': ['D'],
    'D': ['E'],
    'E': []
};

const start = 'A';
const end = 'E';
const allPaths = findPaths(graph, start, end);
console.log(allPaths);
            

Conclusion

In this post, we explained how to represent graphs using JavaScript and how to solve the path-finding problem using DFS. Understanding the essence and applications of graphs is very important as they are useful for solving various real-life problems. I hope you will develop your problem-solving skills by tackling more algorithmic problems in the future.

JavaScript Coding Test Course, Finding the Next Greater Number

Hello! Today we will learn about one of the important topics in JavaScript coding tests, ‘Finding the Next Greater Element’. This problem involves finding the next greater number for each element in an array, requiring efficient algorithm design. In this article, we will cover the problem description, approach, and algorithm implementation in detail.

Problem Description

The problem is to find the first number that appears to the right of each element in the given array that is larger than that element. If there is no such number, return -1.

Examples

  • Input: [2, 3, 3, 5, 4, 9, 6]

    Output: [3, 5, 5, 9, 9, -1, -1]
  • Input: [1, 2, 3, 4]

    Output: [2, 3, 4, -1]
  • Input: [5, 4, 3, 2, 1]

    Output: [-1, -1, -1, -1, -1]

Approach to the Problem

There are two approaches to solving this problem. The first is using a simple nested loop, and the second is using a stack. The second method is more efficient in terms of time complexity.

1. Nested Loop Approach

This method involves checking all elements to the right of each element to find the next greater element. Although this method is easy to implement, it has a time complexity of O(N^2), making it inefficient.


function findNextGreaterElements(arr) {
    const result = [];
    const n = arr.length;
    
    for (let i = 0; i < n; i++) {
        let found = false;
        for (let j = i + 1; j < n; j++) {
            if (arr[j] > arr[i]) {
                result[i] = arr[j];
                found = true;
                break;
            }
        }
        if (!found) {
            result[i] = -1;
        }
    }
    return result;
}

// Example usage
console.log(findNextGreaterElements([2, 3, 3, 5, 4, 9, 6]));
// Output: [3, 5, 5, 9, 9, -1, -1]
    

2. Stack Approach

This method uses a stack to solve the problem. Since this method processes each element using a stack, it has a time complexity of O(N) and a space complexity of O(N).

The algorithm is as follows:

  1. Initialize the stack.
  2. Iterate over each element.
  3. If the top element of the stack is smaller than the current element, pop it from the stack and set its next greater element to the current element.
  4. Push the index of the current element onto the stack.
  5. At the end of the iteration, set remaining elements in the stack to -1.

function findNextGreaterElements(arr) {
    const result = new Array(arr.length).fill(-1);
    const stack = [];
    
    for (let i = 0; i < arr.length; i++) {
        while (stack.length > 0 && arr[stack[stack.length - 1]] < arr[i]) {
            const index = stack.pop();
            result[index] = arr[i];
        }
        stack.push(i);
    }
    
    return result;
}

// Example usage
console.log(findNextGreaterElements([2, 3, 3, 5, 4, 9, 6]));
// Output: [3, 5, 5, 9, 9, -1, -1]
    

Conclusion

The problem of finding the next greater element is a great way to develop algorithmic problem-solving skills by identifying larger numbers that appear later based on the elements of an array. It is important to understand and apply both the simple approach using loops and the efficient approach using stacks. I hope you continue to study more algorithms and data structures through such problems!

References

  • Data structures and algorithms: lectures and books
  • Online coding test platforms (e.g., LeetCode, HackerRank)
  • Official JavaScript documentation