JavaScript Coding Test Course, Minimum Spanning Tree

Coding tests are a great way to evaluate programming skills. Today, we will look at how to solve the Minimum Spanning Tree (MST) problem.
This problem is applicable in various fields, especially in problems related to computer networks.
There are several algorithms to construct a minimum spanning tree, but particularly Kruskal’s Algorithm and Prim’s Algorithm are widely used.

Problem Description

Let’s solve the problem of finding a minimum spanning tree given the edges that represent the graph below.
Each edge is assigned a weight, and we need to find a connected graph where the total weight is minimized.

Problem Definition

    Input:
        [(1, 2, 4), (1, 3, 1), (2, 3, 2), (2, 4, 5), (3, 4, 8), (1, 4, 3)]
    Output:
        List of edges in the minimum spanning tree: [(1, 3, 1), (2, 3, 2), (1, 4, 3), (2, 4, 5)]
        Sum of minimum weights: 11

Problem Solving Process

Step 1: Understanding Graph Data Structure

A graph consists of vertices (nodes) and edges.
Here, edges are provided in the form of tuples as `(start vertex, end vertex, weight)`.
We need to construct the graph using this data.

Step 2: Sorting Edges

Kruskal’s Algorithm first sorts the edges based on their weights.
We sort the given list of edges in ascending order to be able to select the edges with the minimum weights.

Step 3: Cycle Detection Using Union-Find Structure

To check whether a cycle occurs when adding edges, we use the Union-Find data structure.
This data structure has two main functions:

  • Find: Find which set a specific element belongs to
  • Union: Merge the sets that two elements belong to

If no cycle occurs, we select the edge; otherwise, we ignore the edge.
We define the basic Union-Find class and its methods required to implement the algorithm.

Step 4: Implementing MST

Now we will combine the implementations of all steps to ultimately find the MST.
Below is an example of the Kruskal’s algorithm implemented in JavaScript.

    class UnionFind {
        constructor(size) {
            this.parent = Array.from({length: size}, (_, index) => index);
            this.rank = Array(size).fill(1);
        }

        find(node) {
            if (this.parent[node] !== node) {
                this.parent[node] = this.find(this.parent[node]);
            }
            return this.parent[node];
        }

        union(node1, node2) {
            const root1 = this.find(node1);
            const root2 = this.find(node2);
            if (root1 !== root2) {
                if (this.rank[root1] > this.rank[root2]) {
                    this.parent[root2] = root1;
                } else if (this.rank[root1] < this.rank[root2]) {
                    this.parent[root1] = root2;
                } else {
                    this.parent[root2] = root1;
                    this.rank[root1]++;
                }
            }
        }

        connected(node1, node2) {
            return this.find(node1) === this.find(node2);
        }
    }

    function kruskal(edges, numVertices) {
        edges.sort((a, b) => a[2] - b[2]); // Sort edges by weight
        const uf = new UnionFind(numVertices);
        const mst = [];
        let totalWeight = 0;

        for (const [u, v, weight] of edges) {
            if (!uf.connected(u - 1, v - 1)) {
                uf.union(u - 1, v - 1);
                mst.push([u, v, weight]);
                totalWeight += weight;
            }
        }

        return { mst, totalWeight };
    }

    const edges = [
        [1, 2, 4],
        [1, 3, 1],
        [2, 3, 2],
        [2, 4, 5],
        [3, 4, 8],
        [1, 4, 3]
    ];
    const numVertices = 4;

    const { mst, totalWeight } = kruskal(edges, numVertices);
    console.log("List of edges in the minimum spanning tree:", mst);
    console.log("Sum of minimum weights:", totalWeight);

Step 5: Analyzing Results

The results obtained through the implemented algorithm are as follows.
We analyze whether the algorithm works correctly by checking the list of edges in the minimum spanning tree and the total weight.
As a result, we successfully formed the minimum spanning tree based on the given edges.

  • List of edges in the minimum spanning tree: [(1, 3, 1), (2, 3, 2), (1, 4, 3), (2, 4, 5)]
  • Sum of minimum weights: 11

Conclusion

Today, we examined how to solve the minimum spanning tree problem using JavaScript.
Various algorithms can be applied using the given list of edges, and we can understand the characteristics of graphs in the process.
While tackling such problems, we can gain experience in algorithm performance analysis and optimization,
and since this is a topic likely to appear in actual coding tests, be sure to practice sufficiently.

JavaScript Coding Test Course, Breadth-First Search

1. Problem Statement

Breadth-First Search (BFS) is one of the search algorithms commonly used in graphs or tree structures. In this tutorial, we will use BFS to solve the “Shortest Path Finding” problem.

Problem: Find the Shortest Path

Write a function to find the shortest path between two nodes in the given graph. The graph is provided in the form of an adjacency list, and the nodes are represented as strings.

Input Format

        graph: {
            "A": ["B", "C"],
            "B": ["A", "D", "E"],
            "C": ["A", "F"],
            "D": ["B"],
            "E": ["B", "F"],
            "F": ["C", "E"]
        }
        start: "A"
        end: "F"
    

Output Format

        ["A", "C", "F"]
    

2. Problem Analysis

The reason we use BFS to find the shortest path is that BFS explores all neighboring nodes at once, guaranteeing the fastest path. Unlike DFS (Depth-First Search), BFS explores all nodes connected to the current node first before moving to the next level. This characteristic makes BFS suitable for shortest path searches.

3. Algorithm Design

Below is the basic flow of the shortest path finding algorithm using BFS:

  1. Add the starting node to the queue and mark it as visited.
  2. Remove a node from the queue and check all its neighbor nodes.
  3. Add any unvisited neighbor nodes to the queue and set the parent of that node to the current node.
  4. Repeat steps 2-3 until the ending node is found.
  5. When reaching the end node, backtrack through the parent nodes to construct the shortest path.

4. Code Implementation

Below is the implementation code for the shortest path finding function using BFS:

        function findShortestPath(graph, start, end) {
            // Object for queue and marking visited nodes
            let queue = [start];
            let visited = {};
            let parent = {};
            
            visited[start] = true;
            parent[start] = null;

            while (queue.length > 0) {
                let currentNode = queue.shift(); // Remove node from queue
                
                // If the end node is reached
                if (currentNode === end) {
                    return reconstructPath(parent, start, end);
                }

                // Explore the neighbors of the current node
                for (let neighbor of graph[currentNode]) {
                    if (!visited[neighbor]) {
                        visited[neighbor] = true;
                        parent[neighbor] = currentNode; // Set the current node as the parent of the neighbor
                        queue.push(neighbor); // Add the neighbor to the queue
                    }
                }
            }
            return []; // Return empty array if there is no path
        }

        function reconstructPath(parent, start, end) {
            let path = [];
            let current = end;
            while (current !== null) {
                path.push(current);
                current = parent[current];
            }
            return path.reverse(); // Return path in reverse order
        }
    

5. Algorithm Analysis

The code above uses BFS to find the shortest path. The time complexity is O(V + E), where V is the number of nodes and E is the number of edges. This algorithm is memory efficient because it utilizes an adjacency list.

6. Time Complexity and Space Complexity Analysis

The time complexity is O(V + E), as all nodes and edges are explored once. The space complexity is also O(V) because arrays for the queue, visited markers, and parent storage are proportional to the number of nodes.

7. Test Cases

Let’s create a few test cases to check the above code.

        const graph = {
            "A": ["B", "C"],
            "B": ["A", "D", "E"],
            "C": ["A", "F"],
            "D": ["B"],
            "E": ["B", "F"],
            "F": ["C", "E"]
        };

        console.log(findShortestPath(graph, "A", "F")); // Output: ["A", "C", "F"]
        console.log(findShortestPath(graph, "B", "F")); // Output: ["B", "E", "F"]
        console.log(findShortestPath(graph, "D", "A")); // Output: ["D", "B", "A"]
        console.log(findShortestPath(graph, "A", "A")); // Output: ["A"]
    

8. Conclusion

In this tutorial, we solved the shortest path problem using Breadth-First Search (BFS) with JavaScript. BFS is a useful method for traversing graphs using structures like adjacency lists and can be applied to various problems. Continue practicing algorithms and solving more problems.

9. Additional Resources

If you want to learn more algorithm problems and solutions, try using online coding test platforms. You can enhance your skills through various problems and hints available.

© 2023 JavaScript Coding Test Course

JavaScript Coding Test Course, Bellman-Ford

Hello. Today, we will delve into the Bellman-Ford algorithm for those of you preparing for JavaScript coding tests. The Bellman-Ford algorithm is one of the algorithms used to find the shortest path in graph theory, with the advantage that it can be applied even when there are edges with negative weights. In this article, we will cover the overview, principles, problem-solving process, and implementation in JavaScript of the Bellman-Ford algorithm.

1. Overview of the Bellman-Ford Algorithm

The Bellman-Ford algorithm is a graph algorithm used to find the shortest path from one vertex to another. This algorithm has the following characteristics:

  • It can be used even if there are edges with negative weights.
  • It can verify if there are cycles in the graph, or if no negative cycles exist.

2. Principles of the Bellman-Ford Algorithm

The Bellman-Ford algorithm operates on the following principles:

  1. Set the starting vertex and initialize the distance value for that vertex to 0. Set the distance values for all other vertices to infinity.
  2. Examine each edge once to update the shortest distance from the starting vertex to the ending vertex of each edge.
  3. Repeat this process V - 1 times (the shortest path in a graph passes through at most V - 1 edges).
  4. Finally, check all edges again. If any distance values are updated, it is concluded that a negative cycle exists.

3. Problem Statement

Let’s solve the following problem:

Problem:
When given n cities and m roads, each road has a weight that represents the distance from the starting city to the destination city.
Generally, the starting city is city 1, and the destination city is city n.
Write a function to find the shortest distance from city 1 to city n. (There may be negative edges.)

4. Problem-Solving Process

Here is a detailed explanation of how to solve this problem using the Bellman-Ford algorithm:

4.1. Input Data Structure Design

We need to define the input data required to solve the problem. First, we need to design a structure that contains the number of cities, the number of roads, and information about each road. Below is an example of how to represent roads using an array of objects:


    // Number of cities and number of roads
    const n = 5; // Number of cities
    const m = 8; // Number of roads

    // Road information (starting city, destination city, distance)
    const roads = [
        { from: 1, to: 2, weight: 4 },
        { from: 1, to: 3, weight: 2 },
        { from: 2, to: 3, weight: 5 },
        { from: 2, to: 4, weight: 10 },
        { from: 3, to: 2, weight: 1 },
        { from: 3, to: 4, weight: 3 },
        { from: 4, to: 5, weight: 3 },
        { from: 2, to: 5, weight: 12 }
    ];
    

4.2. Initialization

Next, we initialize the distance values. The distance for city 1 is set to 0, and the distances for the other cities are set to infinity:


    const INF = Infinity; // Infinite value
    const distance = Array(n + 1).fill(INF); // Distance array from 1 to n
    distance[1] = 0; // Initialize distance for starting city
    

4.3. Implementing the Bellman-Ford Algorithm

Now, let’s implement the Bellman-Ford algorithm. We will update the distance values by iterating through the edges n-1 times:


    for (let i = 1; i < n; i++) {
        for (const road of roads) {
            if (distance[road.from] + road.weight < distance[road.to]) {
                distance[road.to] = distance[road.from] + road.weight;
            }
        }
    }
    

4.4. Checking for Negative Cycles

Finally, we implement a process to check all edges again to see if there are any negative cycles:


    let hasNegativeCycle = false;

    for (const road of roads) {
        if (distance[road.from] + road.weight < distance[road.to]) {
            hasNegativeCycle = true; // Negative cycle exists
            break;
        }
    }

    if (hasNegativeCycle) {
        console.log("A negative cycle exists.");
    } else {
        console.log("Shortest distance:", distance[n]);
    }
    

5. Complete Code

Putting all the above processes together, we will create a complete JavaScript code:


    function bellmanFord(n, roads) {
        const INF = Infinity;
        const distance = Array(n + 1).fill(INF);
        distance[1] = 0;

        // Bellman-Ford algorithm
        for (let i = 1; i < n; i++) {
            for (const road of roads) {
                if (distance[road.from] + road.weight < distance[road.to]) {
                    distance[road.to] = distance[road.from] + road.weight;
                }
            }
        }

        // Check for negative cycles
        let hasNegativeCycle = false;
        for (const road of roads) {
            if (distance[road.from] + road.weight < distance[road.to]) {
                hasNegativeCycle = true;
                break;
            }
        }

        if (hasNegativeCycle) {
            console.log("A negative cycle exists.");
        } else {
            console.log("Shortest distance:", distance[n]);
        }
    }

    // Example usage
    const n = 5;
    const roads = [
        { from: 1, to: 2, weight: 4 },
        { from: 1, to: 3, weight: 2 },
        { from: 2, to: 3, weight: 5 },
        { from: 2, to: 4, weight: 10 },
        { from: 3, to: 2, weight: 1 },
        { from: 3, to: 4, weight: 3 },
        { from: 4, to: 5, weight: 3 },
        { from: 2, to: 5, weight: 12 }
    ];

    bellmanFord(n, roads);
    

6. Conclusion

In this article, we thoroughly explored the basic concepts and principles of the Bellman-Ford algorithm, as well as the process of solving problems using it. This algorithm is useful when there are edges with negative weights and is one of the important algorithms to learn in graph theory. Since it is a frequently tested topic in coding tests, be sure to understand it well.

I hope you continue to build your skills through various algorithms and problem-solving, and feel free to leave any questions in the comments. Thank you!

Javascript Coding Test Course, ‘Finding the Good Number’

Introduction

Having a basic understanding of programming languages is essential for solving algorithm problems, which are a crucial element of coding tests. In particular, JavaScript is a language that is essential for web development and frontend fields, and many companies are presenting problems using JavaScript. In this course, we will learn the applicability of JavaScript through the problem of ‘Good Numbers’ and explain the algorithm problem-solving process in detail.

Problem Description

The ‘Good Numbers’ problem is about finding numbers that satisfy certain conditions among the given numbers. The specifics of this problem are as follows:

Problem: Given an array of positive integers, write a function that removes duplicates from the array and prints all numbers less than 10. Additionally, calculate the average of the remaining numbers up to one decimal place and return it.

Input and Output Format

Input: An array of positive integers arr ([1, 2, 2, 3, 10, 5, 7, 15])
Output:
1. List of numbers less than 10 after removing duplicates
2. Average of the remaining numbers (up to one decimal place)

Example

    Input: [1, 2, 2, 3, 10, 5, 7, 15]
    Output: 
    Numbers after removing duplicates (less than 10): [1, 2, 3, 5, 7]
    Average: 3.6
    

Problem-Solving Approach

To solve the problem, we need to follow the steps of removing duplicates from the array and calculating the average of the filtered array. We will look at how to perform these tasks step by step using JavaScript.

Step 1: Remove Duplicates

We can use the Set object to remove duplicate elements from the array. The Set object does not allow duplicates automatically, so we can easily obtain the desired result using this object.


const arr = [1, 2, 2, 3, 10, 5, 7, 15];
const uniqueArr = [...new Set(arr)];
console.log(uniqueArr); // [1, 2, 3, 10, 5, 7, 15]
    

Step 2: Filtering

Now, we will perform the task of filtering numbers less than 10 from the array with duplicates removed. We can use JavaScript’s filter() method to extract only the elements that meet the condition.


const filteredArr = uniqueArr.filter(num => num < 10);
console.log(filteredArr); // [1, 2, 3, 5, 7]
    

Step 3: Calculate Average

To calculate the average of the filtered array, we can use the reduce() method. We can get the average by summing all the elements of the array and dividing the total by the number of elements.


const average = filteredArr.reduce((acc, num) => acc + num, 0) / filteredArr.length;
console.log(average.toFixed(1)); // 3.6
    

Complete Code

Now, we will integrate all the described processes into a single function to write the final code.


function goodNumbers(arr) {
    const uniqueArr = [...new Set(arr)];
    const filteredArr = uniqueArr.filter(num => num < 10);
    const average = filteredArr.reduce((acc, num) => acc + num, 0) / filteredArr.length;
    return {
        filteredNumbers: filteredArr,
        average: average.toFixed(1)
    };
}

const inputArr = [1, 2, 2, 3, 10, 5, 7, 15];
const result = goodNumbers(inputArr);
console.log(result);
    

Result

When the code above is executed, the following result can be obtained.


{
    filteredNumbers: [1, 2, 3, 5, 7],
    average: "3.6"
}
    

Optimization and Considerations

The above problem-solving method works well in practical applications. However, when dealing with large datasets, additional considerations regarding performance may be necessary. For example, while using a Set is a convenient way to extract unique values, it may lead to increased memory usage if the size of the array is very large. In such cases, several methods can be considered to improve the algorithm’s performance:

  • Explore methods to remove duplicates and filter at the same time.
  • Improve performance based on the choice of data structure.

Conclusion

In this course, we explored the process of solving the ‘Good Numbers’ problem using JavaScript. By removing duplicates, filtering numbers according to conditions, and calculating averages, we were able to enhance our basic algorithm problem-solving skills. It is important to practice solving such problems frequently while preparing for coding tests. I hope you gain a deeper understanding by utilizing the various features of JavaScript.

Did You Find This Helpful?

If this course has helped you prepare for JavaScript coding tests, try challenging other algorithm problems as well. Feel free to leave any difficulties or questions in the comments. I hope you have the opportunity to share your learning journey and grow together.

JavaScript Coding Test Course, Hacking Effectively

JavaScript is one of the most important languages in web development, and its significance is further highlighted in algorithm problem solving. Many companies evaluate applicants’ problem-solving skills and coding abilities through coding tests. This article will detail the overall approach to coding tests and the problem-solving process through algorithm problems that can be solved with JavaScript.

Problem Description

Problem 1: Sum of Two Numbers

Given an integer array nums and an integer target, write a function that returns the indices of the two numbers in the array that add up to target.

For example:

  • If nums = [2, 7, 11, 15] and target = 9, it should return [0, 1]. (2 + 7 = 9)

Approach to the Problem

To solve this problem, you can take the following approach.

  1. Using a nested loop: This method involves iterating through the two elements of the array to calculate the sum. However, the time complexity is O(n2), making it inefficient.
  2. Using a hashmap: This allows solving the problem in one pass. You store the required numbers in a hashmap and check if the difference between the current number and the target exists in the hashmap. The time complexity of this method is O(n).

Solution: Code using Hashmap

function twoSum(nums, target) {
    const map = new Map(); // Initialize the hashmap

    for (let i = 0; i < nums.length; i++) {
        const complement = target - nums[i]; // Calculate the required value

        if (map.has(complement)) {
            return [map.get(complement), i]; // Return the indices
        }
        
        map.set(nums[i], i); // Add the current number to the hashmap
    }
    
    return []; // Return an empty array if no result is found
}

Code Explanation

The code above defines the twoSum function. The function takes two parameters: an integer array nums and an integer target.

  1. Initialize the hashmap (map).
  2. Iterate through the given array nums.
  3. Calculate the complement for each number. (The result of subtracting the current value from the target value)
  4. Check if the hashmap contains the complement. If it does, return the current index and the stored index.
  5. Add the current number to the hashmap.

Review

Using a hashmap to solve the problem was efficient. The reason is that the code operates with a complexity of O(n), allowing it to respond quickly to all input cases. By solving various problems and understanding the solutions while preparing for coding tests, you can gain a deep understanding of algorithms and data structures.

Conclusion

Success in JavaScript coding tests relies on the ability to read and understand problems, as well as the ability to select appropriate algorithms. The sum of two numbers problem discussed today is not particularly complex, but it serves as good practice for developing algorithmic thinking. Keep solving more problems to improve your skills!