Python Coding Test Course, Exploring Combinations

Many people preparing for coding tests find it important to understand various concepts of algorithms and to develop the skills necessary to solve problems. Today, we will explore the concept of ‘combination’ and examine the problem-solving process using this concept.

1. Understanding Combination

A combination represents the number of ways to choose r elements from a given set of n elements, without regard to the order of selection. The formula for calculating the number of combinations is as follows:

C(n, r) = n! / (r! * (n – r)!)

Here, n! denotes n factorial, and n! = n × (n – 1) × (n – 2) × … × 1. Combinations are generally denoted as ‘nCr’, meaning “choosing r out of n”.

Examples of Combinations

For example, suppose we have four elements {A, B, C, D}. The combinations of selecting two from these are as follows:

  • AB
  • AC
  • AD
  • BC
  • BD
  • CD

2. Problem Introduction

Now, let’s solve a problem using combinations. The problem is as follows:

Problem: Given a list of integers, choose k numbers and print all possible combinations.

Input:

  • The first line contains n (1 ≤ n ≤ 20) and k (1 ≤ k ≤ n).
  • The second line contains n integers. These integers are positive integers between 1 and 100.

Output:

  • Print all combinations in ascending order, with each combination on a new line.

3. Problem Solving

To meet the requirements of the problem, we will follow these steps:

3.1 Input Handling

First, we receive inputs for n and k, as well as n integers. We store these values in an appropriate data structure.

3.2 Generating Combinations

To generate combinations, we can use the combinations function from Python’s itertools module. This function generates all combinations of r selections from a given iterable.

3.3 Printing Combinations

After generating the combinations, we sort them and print each combination.

4. Code Implementation

Now, let’s implement the actual code. Below is the Python code written based on the above logic:


import itertools

def generate_combinations(nums, k):
    # Generate k combinations and sort them
    combinations = list(itertools.combinations(sorted(nums), k))
    return combinations

if __name__ == "__main__":
    # Input handling
    n, k = map(int, input("Enter n and k (e.g., 4 2): ").split())
    nums = list(map(int, input(f"Enter {n} integers: ").split()))

    # Generate combinations
    result = generate_combinations(nums, k)

    # Print results
    for combo in result:
        print(" ".join(map(str, combo)))
    

5. Code Explanation

The above code works as follows:

  • It receives n and k as input from the user.
  • It inputs n integers and stores them in a list.
  • It generates k combinations using itertools.combinations.
  • It sorts and prints the generated combinations.

6. Test Cases

Let’s test the code with various inputs:

Input Example 1:

4 2

1 2 3 4

Output Example 1:

1 2

1 3

1 4

2 3

2 4

3 4

Input Example 2:

5 3

5 1 3 2 4

Output Example 2:

1 2 3

1 2 4

1 2 5

1 3 4

1 3 5

1 4 5

2 3 4

2 3 5

2 4 5

3 4 5

7. Conclusion

Today, we learned about the important concept of ‘combinations’ in coding tests and practiced solving a problem using this concept. Combinations are frequently used in various algorithmic problems, so it is important to understand the basic concepts and methods of utilization. I hope this tutorial helps you understand the concept of combinations and develop better skills in using Python. I encourage you to continue building your skills through various algorithm problems!

python coding test course, finding non-squares

Hello, everyone! In this blog post, we will solve an algorithm problem called Finding Non-Square Numbers. This problem is one of the types that frequently appear in coding tests, requiring both mathematical thinking and programming skills. In this article, we will explain the problem description, solution ideas, actual code, and time complexity analysis in detail.

Problem Description

Given a natural number N, write a function to count the number of natural numbers that are not perfect squares among the natural numbers from 1 to N. A perfect square is a number that can be expressed in the form x * x = y for some natural number x. For example, 1 (1 * 1), 4 (2 * 2), 9 (3 * 3), and 16 (4 * 4) are perfect squares.

Input

  • A natural number N (1 ≤ N ≤ 106)

Output

  • Print the count of numbers that are not perfect squares.

Example

Input

N = 10

Output

7

Explanation: The natural numbers from 1 to 10 are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. Among these, 1, 4, and 9 are perfect squares, so there are 10 – 3 = 7 numbers that are not perfect squares.

Solution Idea

To solve this problem, we must follow these steps:

  1. Check whether each natural number from 1 to N is a perfect square.
  2. Count the number of perfect squares and subtract this from N to get the count of non-square numbers.

To find perfect squares, we can square integers from 1 to √N and precompute the perfect squares from 1 to N, then count the number of perfect squares and subtract this from N. This allows us to solve the problem with a time complexity of O(√N).

Implementation

Now, let’s write the code to solve the problem in Python. Below is a function that counts the number of non-square numbers:


import math

def count_non_squares(N):
    if N < 1:
        return 0
    
    # Calculate the number of perfect squares
    square_count = int(math.sqrt(N))
    
    # Count of non-perfect square numbers
    return N - square_count

Code Explanation

  • First, we use math.sqrt(N) to calculate the square root of N. This provides basic information to know how many perfect squares are there among the natural numbers less than or equal to N.
  • Next, we use int() to convert the square root to an integer, representing the count of perfect squares.
  • Finally, we subtract the count of perfect squares from N to print the count of non-perfect square numbers.

Time Complexity Analysis

The time complexity of this problem is O(1). Even when N is large, calculating the square root can be done quickly. Therefore, this algorithm is very efficient.

Conclusion

In this post, we covered the problem of finding non-square numbers. This problem requires simple mathematical thinking and can help cultivate efficient algorithm coding skills for problem-solving. Since it is a type of problem frequently encountered in coding tests, be sure to practice well!

In the next lecture, we will tackle more interesting problems. Thank you!

python coding test course, picking up pebbles

In this post, we will explore problem-solving methods commonly encountered in Python coding tests through an algorithm problem called “Picking Up Pebbles.” We will define the problem, establish a solution strategy, and ultimately provide Python code.

Problem Description

You discovered pebbles while walking along the beach. Each pebble has a different weight. When picking up pebbles, you must pick up two pebbles at a time, and the maximum number you can pick is N.

Your goal is to calculate the minimum number of times you need to pick up to remove all the pebbles’ weights. Additionally, the weights of the pebbles you pick must be selected from those that have not been picked before.

Input Format

The input follows this format:

  • The first line contains the number of weights N.
  • The second line contains the weights of N.

The output should return the minimum number of times you need to pick up to remove all the pebbles’ weights.

Example

Input:
5
1 2 3 4 5

Output:
3

Problem Analysis

When picking the weights of the pebbles, we can pick two pebbles at a time, but we need to choose the weights we pick as diversely as possible. Therefore, to efficiently pick the given weights, we need to include all weights through the smallest number of picks.

Solution Strategy

This problem can be simply explained as a combination problem. Since we can pick two pebbles at a time with each pick, we need to consider half the number of weights. Counting the weights of each pebble and calculating the number of picks based on the count of weights is essential.

Algorithm Implementation

You can solve the problem based on the following algorithm:

  1. Read the number of weights N.
  2. Store each pebble’s weight in a list.
  3. Count the weights of the pebbles.
  4. Calculate the minimum number of picks by rounding up half the number of weights.

Python Code Implementation

The code below implements the above algorithm in Python:

import math

def min_pickups(weights):
    unique_weights = set(weights)
    return math.ceil(len(unique_weights) / 2)

# Taking input
N = int(input("Please enter the number of weights: "))
weights = list(map(int, input("Please enter the weights of the pebbles: ").split()))
result = min_pickups(weights)
print("Minimum number of picks required to remove all pebbles:", result)

Code Explanation

The provided code first defines the min_pickups function. This function calculates the number of unique pebble weights from the input, then returns the final result by rounding up half of that number.

In the main part, it takes user input to create a list containing the weights and passes this list to the min_pickups function to output the results.

Conclusion and Tips

In this tutorial, we learned problem-solving methods for Python coding tests through the “Picking Up Pebbles” problem. Algorithm problems often involve combinations and ordering, so when solving such problems, it’s essential to effectively count weights and construct combinations.

I hope to deepen my understanding of algorithms through various problems in the future. I will continue to provide useful problem-solving methods and coding tips next time as well. Thank you!

python coding test course, making an integer 1

One of the common problems presented in coding tests is finding a way to reduce a given integer to 1. In this tutorial, we will explain the algorithms, approaches, and provide actual coding examples needed to solve this problem in detail. Our goal is to perform the minimum number of operations until the given integer becomes 1.

Problem Description

Given an integer X. The problem is to reduce this X to 1 using the following three operations and find the minimum number of operations required:

  • 1. X - 1
  • 2. X / 2 (only possible if X is divisible by 2)
  • 3. X / 3 (only possible if X is divisible by 3)

For example, when X = 10, it can be calculated as follows:

  • 10 → 9 (1 operation)
  • 9 → 3 (2 operations)
  • 3 → 1 (3 operations)

Therefore, the total number of operations is 3.

Approach to Problem Solving

To solve this problem efficiently, we can use Dynamic Programming (DP). DP involves breaking the problem into smaller subproblems and storing the solutions to those subproblems to reduce redundant calculations. This approach will be explained in detail in the following steps.

Step 1: Initialize DP Table

Create a DP table to store the minimum number of operations required to reduce each index i to 1. The size of the table is set to X + 1.

X = int(input("Enter an integer: "))
dp = [0] * (X + 1)
    

Step 2: Set Base Case

By default, the value of dp[1] is 0 because 1 is already the target, so no additional operations are needed.

dp[1] = 0  # 1 can be represented with 0 operations.
    

Step 3: Set Recurrence Relation

For each integer i, perform all possible operations to update the value of dp[i].

  • First, for the case of subtracting 1 from i: dp[i] = dp[i-1] + 1
  • Then, if i is divisible by 2: dp[i] = min(dp[i], dp[i // 2] + 1)
  • Also, if i is divisible by 3: dp[i] = min(dp[i], dp[i // 3] + 1)

In other words, we update the value of dp[i] with the minimum operations.

Step 4: Derive Final Result

After filling the DP table for all integers, dp[X] will be the desired result, that is, the minimum number of operations needed to reduce X to 1.

for i in range(2, X + 1):
    dp[i] = dp[i - 1] + 1
    if i % 2 == 0:
        dp[i] = min(dp[i], dp[i // 2] + 1)
    if i % 3 == 0:
        dp[i] = min(dp[i], dp[i // 3] + 1)

print("Minimum number of operations:", dp[X])
    

Full Code

Below is the complete code based on the aforementioned explanations:

def min_operations_to_one(X):
    dp = [0] * (X + 1)
    dp[1] = 0  # Base case: 1 can be represented with 0 operations.

    for i in range(2, X + 1):
        dp[i] = dp[i - 1] + 1  # Case of subtracting 1
        if i % 2 == 0:
            dp[i] = min(dp[i], dp[i // 2] + 1)  # Case of dividing by 2
        if i % 3 == 0:
            dp[i] = min(dp[i], dp[i // 3] + 1)  # Case of dividing by 3

    return dp[X]

# User input
X = int(input("Enter an integer: "))
result = min_operations_to_one(X)
print("Minimum number of operations:", result)
    

Complexity Analysis

The above algorithm has a time complexity of O(N). This is because the DP table is filled using a loop iterating over X. The space complexity is also O(N) due to the space required to store the DP array.

Conclusion

In this article, we explained the process of solving the problem of reducing a given integer to 1 using dynamic programming techniques. It is essential to learn various applications of DP in preparation for coding tests. We hope you enhance your skills through more practice problems and achieve great results in coding tests!

Python Coding Test Course, Implementing Absolute Value Heap

In today’s lecture, we will take a detailed look at how to implement an absolute value heap. An absolute value heap is a data structure that finds the minimum or maximum based on the absolute value of the given numbers. It operates similarly to a regular heap but works based on absolute values. This lecture will cover everything from problem definition to algorithm design and implementation.

Problem Definition

To sort the given integers based on their absolute values, we need to write a program that performs the following tasks:

  • An absolute value heap can insert integer values.
  • It can return and remove the minimum value.

The input values are provided as follows:

  • The first line of input contains the number of operations N.
  • Then, N lines follow, each containing an integer X. If X is 0, it returns and removes the minimum value from the heap.

Example Input

    9
    1
    -1
    0
    -2
    0
    2
    0
    -3
    0
    

Example Output

    1
    -1
    2
    -2
    -3
    

Problem-Solving Strategy

The most important aspect of this problem is that we have to sort the integer values based on their absolute values when inserting. Therefore, when inserting integer values, we can initially use Python’s heapq module to implement a min-heap. However, we need to manage the heap based on absolute values ourselves.

The following strategy can be employed:

  1. Transform the input values into a tuple with two elements and insert them into the heap: (absolute value, original value).
  2. When retrieving the minimum value from the heap, return it according to the order of the original value if the absolute values are the same.
  3. When the input is 0, remove and return the minimum value from the heap.

Implementation Steps

Now, let’s implement the absolute value heap based on the above strategy. We can solve the problem using the following code:

    import heapq
    import sys

    input = sys.stdin.readline

    def absolute_heap():
        heap = []
        N = int(input())
        
        for _ in range(N):
            X = int(input().strip())

            if X != 0:
                # Insert the absolute value and original value as a pair into the heap
                heapq.heappush(heap, (abs(X), X))
            else:
                # When 0 is input, remove and return the minimum value
                if heap:
                    print(heapq.heappop(heap)[1])
                else:
                    print(0)

    if __name__ == "__main__":
        absolute_heap()
    

Code Explanation

1. heapq: This is Python’s built-in heap module. It allows us to easily use a min-heap.

2. input: It allows for quick input using sys.stdin.readline.

3. heap: This is a list used to store pairs of absolute values and original values.

4. For each integer X read, if X is not 0, it inserts its absolute value and original value as a pair into the heap.

5. If X is 0, it removes the minimum value from the heap and outputs the original value.

Complexity Analysis

The time complexity of this algorithm is as follows:

  • The time complexity for inserting an element into the heap is O(log N).
  • The time complexity for removing an element from the heap is also O(log N).

Therefore, the overall time complexity of the algorithm is O(N log N).

Conclusion

In this lecture, we understood the concept of an absolute value heap and learned how to implement it in Python. The important aspect of implementing an absolute value heap is managing the original and absolute values properly. Based on what we learned today, we hope you will tackle various problems.

Additional Problems

Try solving the problem below to deepen your understanding of absolute value heaps:

Problem: Write a program to calculate the sum of given numbers using the absolute value heap. Find the minimum value through the absolute value heap and repeat until all inputs are processed.

To solve the above problem, you need to accumulate the values removed from the heap to keep track of the sum. Write the code yourself and apply the principles learned in this lecture.

Reference Materials

Thank you. See you in the next lecture!