python coding test course, game development

Today, we will solve an algorithm problem for game development using Python. In this tutorial, we will enhance our problem-solving skills through algorithm problems and learn various techniques and concepts that can be applied to real game development.

Problem Description

Problem: “Strange Grid” Game

A grid-shaped game board is given, where each cell contains an integer. In the game, the player starts from outside the boundary of the board and can move up to 3 cells. However, the score that the player can move is calculated as the sum of the values of each cell. The player must choose moves in such a way that they ultimately have a score of 0 or more. Find the possible maximum score while visiting all the cells of the game board.

Input

        First line: Size of the grid N (1 ≤ N ≤ 10)
        Next N lines: Each element of the grid (−100 ≤ element ≤ 100)
    

Output

        Maximum achievable score
    

Example Input

    3
    10 -1 2
    -5 20 3
    2 -3 -4
    

Example Output

    32
    

Problem Analysis

This problem requires using the ‘DFS (Depth First Search)’ technique to explore all possible paths and find the maximum score among them. First, we need to define the moving paths for each cell in the grid. According to the given rules, let us explore all possible paths from the starting point to find the highest total score.

Problem Solving Process

1. Set Up Basic Structure

To solve the problem, we will implement DFS using a recursive function. The recursive function will explore all possible paths from the current position. Here is the basic framework.

def dfs(x, y, score):
    # Function to explore all possible paths from the current position and return the maximum score
    pass
    

2. Implement Path Exploration Logic

Now, we should be able to calculate the positions when moving up, down, left, and right from each cell. To do this, we will use a direction array. We can use the following direction array to explore paths.

dx = [0, 1, 0, -1] # Left and Right
dy = [1, 0, -1, 0] # Up and Down

3. Implement Recursive Function

Now let’s recursively move within the DFS function and calculate the scores. We will check the possibility of movement based on the size of the grid and the current score, and set the boundary condition.

def dfs(x, y, score, visited):
    if x < 0 or x >= N or y < 0 or y >= N or visited[x][y]:
        return score
    
    visited[x][y] = True
    score += grid[x][y] # Add the score of the current position to the current score.
    
    max_score = score
    for i in range(4):
        new_x = x + dx[i]
        new_y = y + dy[i]
        max_score = max(max_score, dfs(new_x, new_y, score, visited))
    
    visited[x][y] = False # Backtracking
    return max_score

4. Implement Main Function

To start exploring all paths, we need to define the main function. In this function, we will read the grid input and start DFS exploration. Finally, we output the maximum score.

def main():
    global grid, N
    N = int(input())
    grid = [list(map(int, input().split())) for _ in range(N)]
    
    visited = [[False]*N for _ in range(N)]
    max_total_score = 0
    
    # Start DFS from all positions.
    for i in range(N):
        for j in range(N):
            max_total_score = max(max_total_score, dfs(i, j, 0, visited))
    
    print(max_total_score)

5. Full Code

The complete code that integrates all parts is as follows.

def dfs(x, y, score, visited):
    if x < 0 or x >= N or y < 0 or y >= N or visited[x][y]:
        return score
    
    visited[x][y] = True
    score += grid[x][y]
    
    max_score = score
    for i in range(4):
        new_x = x + dx[i]
        new_y = y + dy[i]
        max_score = max(max_score, dfs(new_x, new_y, score, visited))
    
    visited[x][y] = False
    return max_score

def main():
    global grid, N
    N = int(input())
    grid = [list(map(int, input().split())) for _ in range(N)]
    
    visited = [[False]*N for _ in range(N)]
    max_total_score = 0
    
    for i in range(N):
        for j in range(N):
            max_total_score = max(max_total_score, dfs(i, j, 0, visited))
    
    print(max_total_score)

if __name__ == "__main__":
    main()

Conclusion

Through this problem, we learned how to utilize DFS to explore paths and maximize points in a game environment. By solving coding problems through algorithms, we can enhance our effectiveness as game developers.

Additional Learning Resources

Referencing the following materials can provide deeper learning:

python coding test course, I don’t want to be a liar

Problem Description

In our neighborhood, there are N people. Each person has their own nickname, and some of them tell lies to each other. A lie is simply the act of leaving ‘their nickname’ to the other person and breaking a promise. You want to find the nicknames of those who actually lied in this situation.

Information is provided about the N people as follows:

  • Their own nickname
  • The number of lies they told to each other

Input Format

The first line contains N (1 ≤ N ≤ 100,000). From the second line onward, N lines contain each person’s nickname and the number of lies that person told.

Output Format

Print the nicknames of liars one per line. If there are no liars, print the message “No liars found.”

Example

    Input:
    3
    Younghee 1
    Cheolsu 0
    Minsu 2

    Output:
    Younghee
    Minsu
    

Solution

To solve this problem, we need to identify each individual’s nickname and the number of lies they told based on the given input. The process of solving the problem using the provided data structure is as follows:

Step 1: Data Structure Design

To handle each person’s information, we will use a list to store the nicknames of the people and the number of lies they told. In this case, we should use a tuple or dictionary to store each person’s information.

Step 2: Collect Input Data

When receiving input from the user, we first read the number of people N, and then for the next N lines, we read each person’s information. In this process, we separate and store each piece of information.

Step 3: Extract Liars

To extract liars, we need to store the nicknames of all individuals whose number of lies is greater than 0. We will use a conditional statement to check the number of lies for each individual.

Step 4: Output Results

Finally, we will print the extracted list of nicknames. If the list is empty, we will print the message “No liars found.”

Code Implementation

Now, let’s implement the code based on the above logic:

def find_liars(n, people):
    liars = []
    
    for name, lies in people:
        if lies > 0:
            liars.append(name)
    
    if liars:
        return liars
    else:
        return ["No liars found."]

if __name__ == "__main__":
    n = int(input("Enter the number of people: "))
    people = []

    for _ in range(n):
        entry = input("Enter name and number of lies: ").split()
        name = entry[0]
        lies = int(entry[1])
        people.append((name, lies))

    result = find_liars(n, people)
    for liar in result:
        print(liar)

Code Explanation

The code above simply returns the entire process. At each step, it stores the information entered by the people and determines the nicknames of those who lied based on this information.

Function Explanation

  • find_liars(n, people): Accepts the given number of people and their information, returning a list of nicknames of those who lied.
  • if __name__ == "__main__":: The main program execution part, which processes the input received from the user.

Conclusion

Through this problem, we solved a common type of problem in coding tests based on understanding simple data structures and lists. I hope the process of solving this problem helps you in preparing for coding tests.

Python Coding Test Course, Finding the Largest Square

One of the common problems that often appears in coding tests is finding the largest square in a two-dimensional array. This problem can be defined as follows.

Problem Definition

Given a binary matrix (a two-dimensional array consisting of 0s and 1s), find the area of the largest square composed of 1s.

For example, let’s assume we have the following matrix.

    [
        [1, 0, 1, 0, 0],
        [1, 0, 1, 1, 1],
        [1, 1, 1, 1, 1],
        [1, 0, 0, 1, 0]
    ]
    

In the matrix above, the largest square is the area from (1, 1) to (3, 3), with an area of 9.

Problem Approach and Solution Process

To solve this problem, we can use the Dynamic Programming method. This methodology breaks the problem down into smaller subproblems and uses the results to derive the final outcome.

Approach Using Dynamic Programming

1. First, we will get the size of the given matrix and define a 2D array dp for dynamic programming. Each element of this dp array will represent the length of one side of the largest square at a specific position.

2. Initialization: Initialize each element of the dp array to 0. However, the first row and first column of the given matrix should be set to 1 only for positions in the original matrix where there is a 1.

3. Filling the dp array: By examining each element of the binary matrix, if the value at a specific position (i, j) is 1, then dp[i][j] is set to the minimum of dp[i-1][j], dp[i][j-1], dp[i-1][j-1] plus 1. This is how we calculate the sides of the largest square.

4. Result: We need to find the largest value in the dp array, and the square of this value will be the area of the square we are looking for.

Implementation of Dynamic Programming

Now, let’s write a Python code based on the above method.

    
def maximalSquare(matrix):
    if not matrix:
        return 0

    max_square_len = 0
    rows = len(matrix)
    cols = len(matrix[0])
    dp = [[0] * cols for _ in range(rows)]

    for i in range(rows):
        for j in range(cols):
            if matrix[i][j] == '1':
                if i == 0 or j == 0:
                    dp[i][j] = 1
                else:
                    dp[i][j] = min(dp[i-1][j], dp[i][j-1], dp[i-1][j-1]) + 1

                max_square_len = max(max_square_len, dp[i][j])

    return max_square_len * max_square_len
    
    

Code Explanation

The first line of the code checks whether the given matrix is empty. If it is empty, the result is 0.

Next, it retrieves the number of rows and columns in the matrix and creates the dp array. This array has the same size as the given binary matrix and is initialized to 0.

Using a loop, we iterate through each element, processing only when the current element is 1. During this process, we fill the dp array using the previously mentioned relationships. Here, we always track and update the length of the largest square’s side.

Finally, we return the area of the largest square.

Complexity Analysis

The above algorithm has a time complexity of O(n * m), where n is the number of rows in the matrix and m is the number of columns. The space complexity is O(n * m), which is the space needed to store the dp array.

Let’s Try with an Example

Now, let’s use this function to find the largest square in the given matrix.

    
matrix = [
    ["1", "0", "1", "0", "0"],
    ["1", "0", "1", "1", "1"],
    ["1", "1", "1", "1", "1"],
    ["1", "0", "0", "1", "0"]
]
print(maximalSquare(matrix))  # 9
    
    

Conclusion

This problem is one of the frequently encountered types in coding tests. If you can understand and solve this problem well through practice, it will greatly help you to solve similar problems. Moreover, the ability to understand and apply the principles of dynamic programming is useful for solving various algorithmic problems.

Additionally, you can also tackle more complex variations of this problem by extending the binary matrix into more intricate forms. For example, there are various types of problems where the structure of 0s and 1s changes in the given matrix, or where you need to find different shapes of squares or rectangles that satisfy given conditions.

Moving Forward

Continue to practice solving more algorithm problems and optimizing by considering time complexity, space complexity, and so on. Deepening your understanding of frequently used data structures and algorithms is also very important. Furthermore, as you encounter various problems, your problem-solving skills will naturally improve.

We hope to help you grow your coding skills through many algorithm courses in the future!

Python Coding Test Course, Finding the Fastest Bus Route

This course covers the problem of Finding the Fastest Bus Route, which is frequently presented in actual job exam algorithm problems. This problem can be solved using graph theory and shortest path algorithms. Throughout the course, we will enhance our algorithm problem-solving skills and learn various techniques necessary for writing Python code.

Problem Description

There is a city with N vertices from 1 to N. There are several bus routes between each pair of vertices, and each bus route has a departure and arrival vertex along with a travel time. Based on the given information, find the fastest route from vertex 1 to vertex N and the time it takes.

Input Format

  • The first line contains the number of vertices N (1 ≤ N ≤ 1000) and the number of bus routes M (1 ≤ M ≤ 10000).
  • The next M lines provide the information for each bus route in the format u v w, where w is the travel time from u to v (1 ≤ w ≤ 10000).

Output Format

  • Print the fastest travel time from vertex 1 to vertex N. If there is no route, print -1.

Problem Solving Process

1. Understanding the Problem

This problem is a representative type of graph problem in finding the shortest path. When bus routes are represented as a graph, each vertex corresponds to a bus stop, edges represent bus routes, and the weights of the edges can be thought of as the travel times. What we want to solve is the fastest way to move from vertex 1 to vertex N.

2. Selecting the Algorithm

There are various algorithms to find the shortest path, but here we will use the Dijkstra’s Algorithm. Dijkstra’s algorithm is efficient for finding the shortest paths in graphs with non-negative weights. Since the travel times for the given bus routes are all positive, this algorithm is appropriate.

3. Implementing the Algorithm

The basic idea of Dijkstra’s algorithm is to maintain an array that records the shortest path distances to each vertex while selecting the vertex with the currently shortest distance. The detailed implementation process is as follows.

# Import required libraries
import sys
import heapq

def dijkstra(N, edges):
    # Initialize distance array
    distance = [float('inf')] * (N + 1)
    distance[1] = 0  # Distance to starting vertex 1 is 0
    priority_queue = [(0, 1)]  # (distance, vertex)

    # Initialize graph
    graph = [[] for _ in range(N + 1)]
    for u, v, w in edges:
        graph[u].append((v, w))

    while priority_queue:
        current_distance, current_vertex = heapq.heappop(priority_queue)
        
        if current_distance > distance[current_vertex]:
            continue

        for neighbor, weight in graph[current_vertex]:
            distance_via_neighbor = current_distance + weight
            
            if distance_via_neighbor < distance[neighbor]:
                distance[neighbor] = distance_via_neighbor
                heapq.heappush(priority_queue, (distance_via_neighbor, neighbor))

    return distance[N] if distance[N] != float('inf') else -1

# Input
N, M = map(int, input().split())
edges = [tuple(map(int, input().split())) for _ in range(M)]
result = dijkstra(N, edges)

print(result)

4. Example and Test Cases

To verify the appropriateness of this algorithm, let's consider several input examples.

Example 1

Input:
4 5
1 2 1
1 3 4
2 3 2
3 4 1
2 4 5

Output:
3

Explanation: The shortest path from vertex 1 to vertex 4 is 1 → 2 → 3 → 4, with a total travel time of 3.

Example 2

Input:
3 3
1 2 1
1 3 4
3 2 2

Output:
-1

Explanation: There is no route from vertex 1 to vertex 2, so we output -1.

Conclusion

In this course, we learned how to solve the problem of finding the fastest bus route using Dijkstra's algorithm for the shortest path. I hope this has been helpful in understanding and implementing the algorithm. As you may encounter similar problems in future coding tests, I encourage you to continue practicing.

Python coding test course, finding the longest increasing subsequence

In this course, we will cover the problem of finding the “Longest Increasing Subsequence” (LIS), which is one of the important concepts in Python coding tests. This problem frequently appears in coding algorithm tests of various IT companies and requires efficient algorithm design and implementation skills. Therefore, it is important to understand and practice it properly.

1. Problem Description

The problem is to find the length of the longest increasing subsequence in a given sequence. A subsequence is formed by selecting some elements from the original sequence while maintaining their order. For example, given the sequence [10, 20, 10, 30, 20, 50], the longest increasing subsequence is [10, 20, 30, 50], which has a length of 4.

2. Problem Approach and Understanding

The longest increasing subsequence problem has the following characteristics:

  • The elements of the subsequence must maintain their order in the original sequence.
  • We need to find the length of the subsequence, not the subsequence itself.

To solve this problem, two approaches can be used.

  1. Dynamic Programming approach
  2. Binary Search approach

2.1 Dynamic Programming Approach

Using dynamic programming, we can maintain the length of the longest increasing subsequence based on each element of the sequence. The time complexity of this approach is O(n^2).

The algorithm using dynamic programming can be described as follows:

  1. Initialize dp[i] as the length of the increasing subsequence, setting all values to 1.
  2. For each element i, traverse the previous elements j (j < i), and if arr[j] < arr[i], update dp[i] to dp[j] + 1.
  3. The final result is the maximum value in the dp array.

2.2 Binary Search Approach

The method using binary search is more efficient, with a time complexity of O(n log n). This approach uses an array called ‘tails’ to store the last elements of the longest increasing subsequences found so far.

The algorithm for the binary search approach can be described as follows:

  1. Initialize an empty array.
  2. Traverse the sequence and perform a binary search to find the position to insert the current element in the tails array.
  3. If the found position is equal to the length of the tails array, add the current element; otherwise, update that position with the current element.
  4. The final result is the length of the tails array.

3. Algorithm Implementation

3.1 Dynamic Programming Implementation

def longest_increasing_subsequence(arr):
    n = len(arr)
    dp = [1] * n  # Initialization
    for i in range(n):
        for j in range(i):
            if arr[j] < arr[i]:
                dp[i] = max(dp[i], dp[j] + 1)
    return max(dp)

3.2 Binary Search Implementation

from bisect import bisect_left

def longest_increasing_subsequence(arr):
    tails = []
    for x in arr:
        i = bisect_left(tails, x)  # Find index of the first element greater than x
        if i == len(tails):
            tails.append(x)  # Add new element
        else:
            tails[i] = x  # Update element
    return len(tails)

4. Examples and Results

Now we will run some examples using the algorithms implemented above.

arr = [10, 20, 10, 30, 20, 50]
print(longest_increasing_subsequence(arr))  # Output: 4

arr = [3, 2, 5, 6, 3, 7, 1]
print(longest_increasing_subsequence(arr))  # Output: 5

arr = [1, 2, 3, 4, 5]
print(longest_increasing_subsequence(arr))  # Output: 5

5. Conclusion

The problem of finding the longest increasing subsequence frequently appears in coding interviews, and can be solved using both dynamic programming and binary search approaches. Through this problem, you can learn both the concept of dynamic programming and the application of binary search, laying the foundation for solving complex algorithm problems.

This concludes the Python coding test course on finding the longest increasing subsequence. I hope this has been helpful in solving algorithm problems. Keep practicing to improve your algorithm skills and prepare for the next coding test!