Problem Description<\/h2>\n
\n The company is trying to develop a new Blu-ray disc production system. Each Blu-ray disc has a specific size, and it must be optimized to store the maximum amount of data. Based on the given capacity of the Blu-ray and the sizes of each file, write a program that can fit as many files as possible onto the Blu-ray.\n <\/p>\n
\nProblem Definition:<\/strong> Given N files, each with a positive integer size, and a given capacity C of the Blu-ray, write a program to calculate the maximum number of files that can fit without exceeding the Blu-ray’s capacity.\n <\/p>\n \nInput Format:<\/strong> \nOutput Format:<\/strong> \n This problem involves finding the maximum number of files that can be combined without exceeding the capacity C of the Blu-ray. To maximize the number of files that can fit on the Blu-ray, the files must be sorted appropriately in advance, and a suitable search method must be used to solve the problem.\n <\/p>\n \n The basic strategy to solve the problem is as follows:\n <\/p>\n \n Let’s look at the process of solving the problem step by step.\n <\/p>\n \n First, we get the capacity of the Blu-ray, the number of files, and the sizes of the files. Input takes place via standard input. We can use Python’s input() function to receive the data.\n <\/p>\n \n Sort the input file sizes in ascending order. This is necessary to ensure we add the smallest files first. Python’s sorted() function can easily sort the data.\n <\/p>\n \n While iterating through the sorted file list, check if adding the current file would exceed the total capacity C of the Blu-ray. If it does not exceed, add the current file to the Blu-ray and count the number of files.\n <\/p>\n \n After iterating through all the files, output the final count of files that can fit on the Blu-ray.\n <\/p>\n
\n The first line contains the capacity C of the Blu-ray (1 \u2264 C \u2264 10000) and the number of files N (1 \u2264 N \u2264 100).
\n The second line contains the sizes of N files (1 \u2264 file size \u2264 1000).\n <\/p>\n
\n Print the maximum number of files that can fit on the Blu-ray.\n <\/p>\n<\/section>\nProblem Analysis<\/h2>\n
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Problem Solving Process<\/h2>\n
Step 1: Input<\/h3>\n
Step 2: Data Sorting<\/h3>\n
Step 3: Add Files and Sum Sizes<\/h3>\n
Step 4: Output Result<\/h3>\n
Step 5: Complete Code<\/h3>\n
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\ndef maximum_files_in_blu_ray(capacity, files):\n # Sort file sizes\n files.sort()\n count = 0\n total_size = 0\n\n for file in files:\n if total_size + file <= capacity:\n total_size += file\n count += 1\n else:\n break\n\n return count\n\n# Get input\ncapacity, n = map(int, input().split())\nfiles = list(map(int, input().split()))\n\n# Call function and output result\nresult = maximum_files_in_blu_ray(capacity, files)\nprint(result)\n<\/code>\n <\/pre>\n<\/section>\nExample Input and Output<\/h2>\n
Example 1<\/h3>\n