\n Given an integer array Indices of the two elements or \n This problem uniquely asks to obtain \n To solve this problem, we will traverse the array only once and calculate the remainder for each element to match the target condition. \n Now, let’s implement this algorithm in C#. Below is the solution code.\n <\/p>\n \n The time complexity of this algorithm is O(n). We can find the result with a single traversal of the array. \n Let’s write various test cases to verify the functionality.\n <\/p>\n \n In this lecture, we learned how to optimize space and time by using a hash set to solve the problem of finding the sum modulo. <\/body><\/p>\n","protected":false},"excerpt":{"rendered":"numbers<\/code> and an integer target<\/code>,
\n you need to determine if any two elements from the numbers<\/code> array can be added together to yield the remainder of target<\/code>.
\n If possible, return the indices of those two elements, otherwise return -1<\/code>.
\n Each element must be used exactly once, and the same element cannot be chosen twice.\n <\/p>\nInput Format<\/h3>\n
\n
numbers<\/code>: Integer array (0 \u2264 numbers.length \u2264 105<\/sup>, -109<\/sup> \u2264 numbers[i] \u2264 109<\/sup>)<\/li>\ntarget<\/code>: Integer (0 \u2264 target \u2264 109<\/sup>)<\/li>\n<\/ul>\nOutput Format<\/h3>\n
-1<\/code><\/p>\n<\/div>\nSolution Process<\/h2>\n
1. Problem Analysis<\/h3>\n
target<\/code> through the addition of two elements followed by a modulo operation.
\n In other words, if the two numbers we are looking for are x<\/code> and y<\/code>, it must hold that
\n (x + y) % target == target<\/code>. It is essential to understand the implications of the addition and modulo conditions.\n <\/p>\n2. Algorithm Design<\/h3>\n
\n One method involves using a hash set to store previous values and check the condition by calculating the remainder with the current value.
\n The reason for using a hash set is to maintain an average time complexity of O(1).\n <\/p>\n3. Code Implementation<\/h3>\n
using System;\nusing System.Collections.Generic;\n\npublic class Solution\n{\n public int[] FindTwoElementsWithTargetModulo(int[] numbers, int target)\n {\n \/\/ Dictionary to store the index of elements\n Dictionary4. Time Complexity<\/h3>\n
\n Additionally, the extra space complexity is O(n) due to the storage of values in the hash set.\n <\/p>\n5. Test Cases<\/h3>\n
public class Program\n{\n public static void Main()\n {\n Solution solution = new Solution();\n\n \/\/ Test case 1\n int[] numbers1 = { 1, 2, 3, 4, 5 };\n int target1 = 5;\n int[] result1 = solution.FindTwoElementsWithTargetModulo(numbers1, target1);\n Console.WriteLine(string.Join(\", \", result1)); \/\/ Expected output: 0, 4\n\n \/\/ Test case 2\n int[] numbers2 = { 1, 2, 3, 7 };\n int target2 = 5;\n int[] result2 = solution.FindTwoElementsWithTargetModulo(numbers2, target2);\n Console.WriteLine(string.Join(\", \", result2)); \/\/ Expected output: 0, 2\n\n \/\/ Test case 3\n int[] numbers3 = { 3, 8, 12, 5 };\n int target3 = 10;\n int[] result3 = solution.FindTwoElementsWithTargetModulo(numbers3, target3);\n Console.WriteLine(string.Join(\", \", result3)); \/\/ Expected output: -1\n }\n}\n <\/code><\/pre>\n6. Conclusion<\/h3>\n
\n This approach is very useful for solving various problems that may appear in coding tests.
\n I hope you gain confidence by solving more algorithm problems.\n <\/p>\n<\/div>\n