{"id":33956,"date":"2024-11-01T09:22:23","date_gmt":"2024-11-01T09:22:23","guid":{"rendered":"http:\/\/atmokpo.com\/w\/?p=33956"},"modified":"2024-11-01T10:54:44","modified_gmt":"2024-11-01T10:54:44","slug":"c-coding-test-course-finding-the-diameter-of-a-tree","status":"publish","type":"post","link":"https:\/\/atmokpo.com\/w\/33956\/","title":{"rendered":"C# Coding Test Course, Finding the Diameter of a Tree"},"content":{"rendered":"<p><body><\/p>\n<p>Hello, everyone! Today, we will discuss a problem of finding the diameter of a tree using C#. This article will help you understand through problem definition, algorithm design, implementation, and testing process.<\/p>\n<h2>Problem Definition<\/h2>\n<p>\n    The diameter of a tree refers to the length of the longest path between two nodes in the tree. The given tree is represented by the number of vertices <code>n<\/code> and <code>n-1<\/code> edges.<br \/>\n    Based on this, write a function to calculate the diameter of the tree.\n<\/p>\n<h3>Input<\/h3>\n<ul>\n<li><code>n<\/code> : Number of vertices (2 \u2264 n \u2264 10^5)<\/li>\n<li><code>n-1<\/code> edges that make up the tree. Each edge is given in the form of <code>u v w<\/code>, where <code>u<\/code> and <code>v<\/code> are connected vertices, and <code>w<\/code> is the weight between the two vertices.<\/li>\n<\/ul>\n<h3>Output<\/h3>\n<p>\n    An integer value representing the diameter of the tree.\n<\/p>\n<h2>Algorithm Design<\/h2>\n<p>\n    The most common method to find the diameter of a tree is to use &#8220;two depth-first searches (DFS).&#8221;<br \/>\n    Below is a summary of the simple procedure.\n<\/p>\n<ol>\n<li>Run DFS from an arbitrary vertex to find the farthest vertex <code>A<\/code>.<\/li>\n<li>Run DFS again from vertex <code>A<\/code> to find the farthest vertex <code>B<\/code>, and calculate the distance.<\/li>\n<\/ol>\n<p>\n    This method can efficiently determine the diameter of the tree. In the worst case, the time complexity is <code>O(n)<\/code>.\n<\/p>\n<h2>C# Code Implementation<\/h2>\n<p>Below is the C# code based on the above algorithm:<\/p>\n<pre><code>using System;\nusing System.Collections.Generic;\n\nclass TreeDiameter\n{\n    static List<Tuple<int, int>>[] graph;\n    static bool[] visited;\n    static int maxDistance;\n    static int furthestNode;\n\n    public static void Main()\n    {\n        int n = int.Parse(Console.ReadLine());\n        graph = new List<Tuple<int, int>>[n + 1];\n\n        for (int i = 1; i <= n; i++)\n        {\n            graph[i] = new List<Tuple<int, int>>();\n        }\n\n        for (int i = 0; i < n - 1; i++)\n        {\n            var edge = Console.ReadLine().Split();\n            int u = int.Parse(edge[0]);\n            int v = int.Parse(edge[1]);\n            int w = int.Parse(edge[2]);\n            graph[u].Add(new Tuple<int, int>(v, w));\n            graph[v].Add(new Tuple<int, int>(u, w));\n        }\n\n        \/\/ Finding the farthest vertex using first DFS\n        visited = new bool[n + 1];\n        maxDistance = 0;\n        DFS(1, 0);\n\n        \/\/ Finding the diameter using second DFS\n        visited = new bool[n + 1];\n        maxDistance = 0;\n        DFS(furthestNode, 0);\n        \n        \/\/ Output the result\n        Console.WriteLine(maxDistance);\n    }\n\n    static void DFS(int node, int distance)\n    {\n        visited[node] = true;\n\n        if (distance > maxDistance)\n        {\n            maxDistance = distance;\n            furthestNode = node;\n        }\n\n        foreach (var neighbor in graph[node])\n        {\n            if (!visited[neighbor.Item1])\n            {\n                DFS(neighbor.Item1, distance + neighbor.Item2);\n            }\n        }\n    }\n}\n<\/code><\/pre>\n<h3>Code Explanation<\/h3>\n<p>\n    1. <code>graph<\/code>: An array to store the edges of the tree in an adjacency list format.<br \/>\n    2. <code>visited<\/code>: An array to track visited vertices during DFS.<br \/>\n    3. <code>maxDistance<\/code>: Stores the length of the longest path found so far.<br \/>\n    4. <code>furthestNode<\/code>: Stores the ID of the farthest vertex.<br \/>\n    5. <code>Main()<\/code>: Receives the tree structure input and calls DFS twice to calculate the diameter of the tree.<br \/>\n    6. <code>DFS(int node, int distance)<\/code>: Implements the depth-first search function to recursively explore each vertex while updating the distance.\n<\/p>\n<h2>Test Cases<\/h2>\n<p>Your code can be validated with the following test cases:<\/p>\n<h3>Test Input<\/h3>\n<pre><code>5\n1 2 3\n1 3 2\n3 4 4\n3 5 1\n<\/code><\/pre>\n<h3>Expected Output<\/h3>\n<pre><code>9\n<\/code><\/pre>\n<h3>Description<\/h3>\n<p>\n    If we draw the tree from the above input, it looks like this:\n<\/p>\n<pre>\n          1\n         \/ \\\n        2   3\n           \/ \\\n          4   5\n<\/pre>\n<p>\n    The diameter of the tree is the path starting from node <code>2<\/code> to node <code>4<\/code>, with a total length of <code>3 + 2 + 4 = 9<\/code>.\n<\/p>\n<h2>Conclusion<\/h2>\n<p>\n    Today, we solved the problem of finding the diameter of a tree using C#.<br \/>\n    This algorithm is a frequently encountered type in tree problems, so I encourage you to practice sufficiently.<br \/>\n    Try various test cases to deepen your understanding.<br \/>\n    Thank you!\n<\/p>\n<p><\/body><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Hello, everyone! Today, we will discuss a problem of finding the diameter of a tree using C#. This article will help you understand through problem definition, algorithm design, implementation, and testing process. Problem Definition The diameter of a tree refers to the length of the longest path between two nodes in the tree. 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