{"id":34606,"date":"2024-11-01T09:29:59","date_gmt":"2024-11-01T09:29:59","guid":{"rendered":"http:\/\/atmokpo.com\/w\/?p=34606"},"modified":"2024-11-01T11:40:31","modified_gmt":"2024-11-01T11:40:31","slug":"javascript-coding-test-course-dictionary-lookup","status":"publish","type":"post","link":"https:\/\/atmokpo.com\/w\/34606\/","title":{"rendered":"Javascript Coding Test Course, Dictionary Lookup"},"content":{"rendered":"<p><body><\/p>\n<div class=\"problem-statement\">\n<h2>Problem Description<\/h2>\n<p>There is a given string <code>s<\/code> and an array of strings <code>dictionary<\/code>. You need to check if the words<br \/>\n    obtained by splitting the string <code>s<\/code> by spaces exist in the <code>dictionary<\/code>.<br \/>\n    If all the words in <code>s<\/code> exist in the <code>dictionary<\/code>, return <code>true<\/code>; otherwise,<br \/>\n    return <code>false<\/code>.<\/p>\n<\/div>\n<div class=\"example\">\n<h2>Examples<\/h2>\n<h3>Example 1<\/h3>\n<p><strong>Input:<\/strong> s = &#8220;apple banana&#8221;, dictionary = [&#8220;apple&#8221;, &#8220;sweet potato&#8221;, &#8220;banana&#8221;] <br \/>\n<strong>Output:<\/strong> true<\/p>\n<h3>Example 2<\/h3>\n<p><strong>Input:<\/strong> s = &#8220;orange grape&#8221;, dictionary = [&#8220;apple&#8221;, &#8220;banana&#8221;] <br \/>\n<strong>Output:<\/strong> false<\/p>\n<\/div>\n<div class=\"solution\">\n<h2>Solution<\/h2>\n<p>To solve this problem, the following steps are necessary:<\/p>\n<ol>\n<li>Split the string <code>s<\/code> by spaces to create a list of words.<\/li>\n<li>Check if all words in the list are included in the <code>dictionary<\/code>.<\/li>\n<li>If all words are included, return <code>true<\/code>; if any word is not included, return<br \/>\n        <code>false<\/code>.<\/li>\n<\/ol>\n<h3>Implementation<\/h3>\n<p>Based on this logic, let&#8217;s write the JavaScript code:<\/p>\n<pre><code>\nfunction isAllWordsInDictionary(s, dictionary) {\n    const words = s.split(\" \"); \/\/ Split words by spaces\n    const dictionarySet = new Set(dictionary); \/\/ Convert to Set for optimized search\n\n    for (const word of words) {\n        if (!dictionarySet.has(word)) { \/\/ Check if each word is in the dictionary\n            return false; \/\/ Return false if any word is not found\n        }\n    }\n    return true; \/\/ Return true if all words are found\n}\n\n\/\/ Example tests\nconsole.log(isAllWordsInDictionary(\"apple banana\", [\"apple\", \"sweet potato\", \"banana\"])); \/\/ true\nconsole.log(isAllWordsInDictionary(\"orange grape\", [\"apple\", \"banana\"])); \/\/ false\n    <\/code><\/pre>\n<h3>Code Explanation<\/h3>\n<p>In the code above, we perform the following steps:<\/p>\n<ul>\n<li><code>s.split(\" \")<\/code>: Splits the given string <code>s<\/code> by spaces to create a list of words.<\/li>\n<li><code>new Set(dictionary)<\/code>: Converts the given <code>dictionary<\/code> array to a Set to remove duplicates and optimize<br \/>\n        search times to O(1).<\/li>\n<li>We use a for loop to check if each word exists in the <code>dictionarySet<\/code>.<\/li>\n<li>If a word does not exist, <code>false<\/code> is returned; if all words exist, <code>true<\/code> is returned.<\/li>\n<\/ul>\n<h3>Time Complexity<\/h3>\n<p>The time complexity of this algorithm is O(n + m), where <code>n<\/code> is the number of words in the string <code>s<\/code> and<br \/>\n    <code>m<\/code> is the number of words in the <code>dictionary<\/code>. The reason for using a Set is to improve the search speed to enhance<br \/>\n    overall performance.<\/p>\n<h3>Conclusion<\/h3>\n<p>This problem allowed us to effectively use strings and arrays to verify whether the given conditions were met.<br \/>\n    When solving algorithm problems, it is always easier to approach them by breaking them down into steps.<br \/>\n    Such problems can also be beneficially utilized in other scenarios.<\/p>\n<\/div>\n<p><\/body><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Problem Description There is a given string s and an array of strings dictionary. You need to check if the words obtained by splitting the string s by spaces exist in the dictionary. If all the words in s exist in the dictionary, return true; otherwise, return false. Examples Example 1 Input: s = &#8220;apple &hellip; <a href=\"https:\/\/atmokpo.com\/w\/34606\/\" class=\"more-link\">\ub354 \ubcf4\uae30<span class=\"screen-reader-text\"> &#8220;Javascript Coding Test Course, Dictionary Lookup&#8221;<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[141],"tags":[],"class_list":["post-34606","post","type-post","status-publish","format-standard","hentry","category-javascript-coding-test"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Javascript Coding Test Course, Dictionary Lookup - \ub77c\uc774\ube0c\uc2a4\ub9c8\ud2b8<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/atmokpo.com\/w\/34606\/\" \/>\n<meta property=\"og:locale\" content=\"ko_KR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Javascript Coding Test Course, Dictionary Lookup - \ub77c\uc774\ube0c\uc2a4\ub9c8\ud2b8\" \/>\n<meta property=\"og:description\" content=\"Problem Description There is a given string s and an array of strings dictionary. You need to check if the words obtained by splitting the string s by spaces exist in the dictionary. If all the words in s exist in the dictionary, return true; otherwise, return false. 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