Hello! In this blog post, we will discuss the Making Maximum Value by Pairing Numbers<\/strong> problem that can be presented in coding tests with JavaScript. This problem requires various algorithmic thinking and provides an opportunity to deepen understanding of optimization problems. The goal is to combine the given numbers to create the largest possible number.<\/p>\n You need to repeatedly combine two given numbers and multiply them to create the maximum value. The detailed problem definition is as follows:<\/p>\n To solve this problem, several key steps are needed.<\/p>\n Let’s write the code to solve this problem with JavaScript. Below is the implemented code.<\/p>\n Let’s analyze each part of the code.<\/p>\n First, we sort the array in descending order. This allows larger numbers to come first, and we calculate the product based on this. Sorting the array in JavaScript can be easily accomplished using the Through a loop, we read the elements of the array two by two and accumulate their product in Finally, we return The time complexity of this algorithm is O(N log N). This is due to the time required to sort the array. The subsequent loop operates at O(N), making the overall operations linear, excluding sorting. The space complexity is O(1), as no additional space is used, making it memory efficient.<\/p>\n Let’s add a few test cases to verify the accuracy of the code.<\/p>\n In this article, we discussed the problem of making maximum value by pairing numbers. We implemented the algorithm by sorting the array and calculating the maximum value. I hope this has been a valuable experience in considering how to efficiently handle immediate processing of arrays.<\/p>\n In coding tests using JavaScript, such optimization problems are often presented, so consistent practice is required. Additionally, I encourage you to challenge yourself with various problems to develop your algorithmic thinking!<\/p>\n <\/body><\/p>\n","protected":false},"excerpt":{"rendered":"Problem Definition<\/h2>\n
\nProblem:<\/strong> Given an array of N natural numbers, write a program that pairs all the numbers two by two to maximize the sum of their products.\n\nInput:<\/strong>\n- The first line contains a natural number N (1 \u2264 N \u2264 1000).\n- The second line contains N natural numbers a1, a2, ..., aN (1 \u2264 ai \u2264 1000).\n\nOutput:<\/strong>\n- Print the maximum value.\n<\/pre>\n
Example of the Problem<\/h2>\n
\nInput:<\/strong>\n5\n1 2 3 4 5\n\nOutput:<\/strong>\n43\n<\/pre>\n
Approach to the Problem<\/h2>\n
\n
Implementation<\/h2>\n
\nfunction maxSumFromPairs(numbers) {\n \/\/ Sort the array in descending order\n numbers.sort((a, b) => b - a);\n \n let maxSum = 0;\n\n \/\/ Pair two and multiply, then sum\n for (let i = 0; i < numbers.length; i += 2) {\n \/\/ If the last element is odd, add the remaining element alone\n if (i === numbers.length - 1) {\n maxSum += numbers[i];\n } else {\n maxSum += numbers[i] * numbers[i + 1];\n }\n }\n return maxSum;\n}\n\n\/\/ Example usage\nconst numbers = [1, 2, 3, 4, 5];\nconsole.log(maxSumFromPairs(numbers)); \/\/ 43\n<\/code><\/pre>\nCode Analysis<\/h2>\n
1. Sorting<\/h3>\n
sort<\/code> method.<\/p>\n2. Pairing and Summing<\/h3>\n
maxSum<\/code>. If the length of the array is odd, the last remaining element is simply added as it is.<\/p>\n3. Returning the Result<\/h3>\n
maxSum<\/code>. The code is simple, but it allows us to efficiently obtain the maximum value.<\/p>\nComplexity Analysis<\/h2>\n
Test Cases<\/h2>\n
\nconsole.log(maxSumFromPairs([3, 5, 1, 2, 4])); \/\/ 47\nconsole.log(maxSumFromPairs([1])); \/\/ 1\nconsole.log(maxSumFromPairs([9, 7, 5, 3])); \/\/ 64\nconsole.log(maxSumFromPairs([1, 1, 1, 1, 1])); \/\/ 5\n<\/code><\/pre>\nConclusion<\/h2>\n