{"id":34660,"date":"2024-11-01T09:30:35","date_gmt":"2024-11-01T09:30:35","guid":{"rendered":"http:\/\/atmokpo.com\/w\/?p=34660"},"modified":"2024-11-01T11:27:06","modified_gmt":"2024-11-01T11:27:06","slug":"swift-coding-test-course-dna-password","status":"publish","type":"post","link":"https:\/\/atmokpo.com\/w\/34660\/","title":{"rendered":"Swift Coding Test Course, DNA Password"},"content":{"rendered":"

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This article deals with algorithm problems that are frequently presented in coding tests, and explains in depth the process of solving those problems. Today’s topic is ‘DNA Password’, where we will solve a password problem based on DNA strings.<\/p>\n<\/header>\n

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Problem Description<\/h2>\n

You need to design a system that generates passwords using DNA strings. The DNA string consists of uppercase letters A, C, G, and T, and each character becomes a component of the password in various combinations.<\/p>\n

You are to find specific patterns in the given DNA string and generate a password based on these patterns. The following is a detailed problem definition:<\/p>\n

Problem Definition<\/h3>\n

Given a string s<\/code> and a natural number k<\/code>, you should consider all substrings of length k<\/code> from s<\/code> and generate a password using the frequency of A, C, G, and T in these substrings.<\/p>\n

The password is defined as the count of substrings where the frequency of A, C, G, and T is at least min_count<\/code>.<\/p>\n

Input Example<\/h3>\n

s = \"ACGTACGTGACG\", k = 4, min_count = 1<\/code><\/p>\n

Output Example<\/h3>\n

3<\/code><\/p>\n

Here, “ACGT”, “CGTA”, and “GTAC” are substrings with frequencies of at least 1.<\/p>\n<\/section>\n

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Problem Solving Strategy<\/h2>\n

The strategy to solve this problem is as follows:<\/p>\n

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  1. Generate substrings of length k<\/code> from the entire string s<\/code>.<\/li>\n
  2. Calculate the frequencies of A, C, G, and T for each substring.<\/li>\n
  3. If the frequencies of A, C, G, and T are at least min_count<\/code>, increase the count.<\/li>\n
  4. Finally, output the count.<\/li>\n<\/ol>\n<\/section>\n
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    Implementation Steps<\/h2>\n

    Now let’s look at how to implement the problem using Swift. Here is the step-by-step code to solve the problem.<\/p>\n

    1. Input<\/h3>\n

    First, we take the string and variables as input. In Swift, values can be received through command-line arguments or direct input.<\/p>\n

    \n\nlet inputString = \"ACGTACGTGACG\"\nlet k = 4\nlet minCount = 1\n<\/code>\n<\/pre>\n
    2. Generate Substrings<\/h3>\n
    Generate all substrings of length k<\/code> from the string.<\/p>\n
    \n\nvar count = 0\nlet length = inputString.count\n\nfor i in 0...(length - k) {\n    let startIndex = inputString.index(inputString.startIndex, offsetBy: i)\n    let endIndex = inputString.index(startIndex, offsetBy: k)\n    let substring = String(inputString[startIndex..\n<\/pre>\n
    3. Frequency Calculation<\/h3>\n
    Calculate the frequencies of each character (A, C, G, T) for the generated substrings.<\/p>\n
    \n\nvar frequencies = [Character: Int]()\n\nfor char in substring {\n    frequencies[char, default: 0] += 1\n}\n\n\/\/ Condition Check\nif frequencies[\"A\"]! >= minCount && \n   frequencies[\"C\"]! >= minCount && \n   frequencies[\"G\"]! >= minCount && \n   frequencies[\"T\"]! >= minCount {\n    count += 1\n}\n<\/code>\n<\/pre>\n
    4. Output Result<\/h3>\n
    Print the final count.<\/p>\n
    \n\nprint(\"Total valid passwords: \\(count)\")\n<\/code>\n<\/pre>\n<\/section>\n
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    Complete Code<\/h2>\n
    Now let's take a look at the complete code that integrates all the steps.<\/p>\n
    \n\nlet inputString = \"ACGTACGTGACG\"\nlet k = 4\nlet minCount = 1\nvar count = 0\nlet length = inputString.count\n\nfor i in 0...(length - k) {\n    let startIndex = inputString.index(inputString.startIndex, offsetBy: i)\n    let endIndex = inputString.index(startIndex, offsetBy: k)\n    let substring = String(inputString[startIndex..= minCount && \n       frequencies[\"C\"]! >= minCount && \n       frequencies[\"G\"]! >= minCount && \n       frequencies[\"T\"]! >= minCount {\n        count += 1\n    }\n}\n\nprint(\"Total valid passwords: \\(count)\")\n<\/code>\n<\/pre>\n<\/section>\n
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    Result<\/h2>\n
    Running this code with the given input will output the number of valid passwords. Understanding the basic algorithm patterns of handling strings and checking conditions is very useful in coding tests.<\/p>\n
    Furthermore, you can enhance your problem-solving skills by testing the code against various input cases and adding exception handling.<\/p>\n<\/section>\n