Output the pairs whose sum equals N.<\/li>\n<\/ol>\nAlgorithm Implementation<\/h2>\n
In Swift, we can solve the problem using the following structure:<\/p>\n
import Foundation\n\nfunc findGoodNumbers(N: Int) {\n var goodPairs: [(Int, Int)] = []\n \n for x in 1...N {\n for y in x...N {\n if x + y == N {\n goodPairs.append((x, y))\n }\n }\n }\n \n \/\/ Output result\n for pair in goodPairs {\n print(\"Good number pair: \\(pair.0), \\(pair.1)\")\n }\n}\n\nlet N = 10 \/\/ Example input\nfindGoodNumbers(N: N)<\/code><\/pre>\nCode Explanation<\/h2>\n
In the Swift code above, we can see the following important details:<\/p>\n
\n- The function
findGoodNumbers<\/code> takes a natural number N as a parameter and finds the pairs of good numbers for it.<\/li>\n- A nested
for<\/code> loop is used to generate all pairs of x<\/code> and y<\/code>.<\/li>\n- If the sum equals N, that pair is added to the
goodPairs<\/code> array.<\/li>\n- Finally, the pairs of good numbers stored in the array are printed.<\/li>\n<\/ol>\n
Execution Result<\/h2>\n
If the input N is 10, the program produces the following output:<\/p>\n
Good number pair: 1, 9\nGood number pair: 2, 8\nGood number pair: 3, 7\nGood number pair: 4, 6\nGood number pair: 5, 5<\/code><\/pre>\nComplexity Analysis<\/h2>\n
The time complexity of this algorithm is O(N^2). Since we use a nested loop for N, the execution time may increase for larger values of N. However, since the maximum value of N is limited to 1000, this level of time complexity is practically feasible.<\/p>\n
Conclusion<\/h2>\n
In this article, we explored the approach to solve the “good number” problem and implemented the solution in Swift code. We learned how to resolve the problem through a simple yet effective nested loop. I hope this helps improve algorithmic thinking through similar problems in the future.<\/p>\n
Additional Considerations<\/h2>\n
Various methods can be explored to solve this problem. For example:<\/p>\n
\n- Using a hashmap to find good numbers with O(N) time complexity<\/li>\n
- When N is even, restricting the range of x to up to N\/2<\/li>\n
- Solutions through recursive methods<\/li>\n<\/ul>\n
Through these various approaches, a deeper understanding of algorithms can be achieved. In the next session, we will address additional problems related to this topic. Thank you!<\/p>\n
<\/body><\/p>\n","protected":false},"excerpt":{"rendered":"
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