If it does not exist, add the current number to the hashmap.<\/li>\n<\/ol>\n4. Code Implementation<\/h3>\n
Now, let’s write the code in Swift based on the above algorithm.<\/p>\n
\n func twoSum(_ nums: [Int], _ target: Int) -> [Int] {\n var numDict = [Int: Int]() \/\/ Hashmap\n for (index, num) in nums.enumerated() {\n let complement = target - num \/\/ Subtract current number from target\n if let complementIndex = numDict[complement] { \/\/ Search in hashmap\n return [complementIndex, index] \/\/ Return indices\n }\n numDict[num] = index \/\/ Add current number to hashmap\n }\n return [] \/\/ Return empty array if no value found\n }\n\n \/\/ Example usage\n let nums = [2, 7, 11, 15]\n let target = 9\n let result = twoSum(nums, target)\n print(result) \/\/ Outputs: [0, 1]\n <\/code><\/pre>\n5. Time Complexity Analysis<\/h3>\n
The time complexity of this algorithm is O(n). This is because we traverse the array once while adding values to the hashmap and checking existing values. The space complexity is O(n), which is proportional to the size of the hashmap.<\/p>\n
Conclusion<\/h2>\n
What is important in Swift coding tests is to understand the problem and choose the appropriate algorithm to solve it efficiently. Through this problem, we learned an approach using a hashmap. Practice various algorithms and data structures to prepare well for coding tests.<\/p>\n
<\/body><\/p>\n","protected":false},"excerpt":{"rendered":"
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