Print the result.<\/li>\n<\/ul>\nKotlin Code Implementation<\/h3>\n
The following code is a Kotlin program that implements all the above procedures:<\/p>\n
\n fun main() {\n \/\/ Input\n val (n, m) = readLine()!!.split(\" \").map { it.toInt() }\n val a = readLine()!!.split(\" \").map { it.toInt() }\n\n \/\/ Calculate remainder sum\n var remainderSum = 0\n for (i in 0 until n) {\n remainderSum += a[i] % m\n }\n\n \/\/ Print result\n println(remainderSum)\n }\n <\/pre>\nCode Explanation<\/h3>\n
In the above code, readLine()<\/code> is used to receive input from the user. The first line inputs the array size N and M, while the second line inputs the elements of array A. Then, a for<\/code> loop is used to calculate the remainders of all elements in A when divided by M and accumulates them in the remainderSum<\/code> variable. Finally, the sum of the calculated remainders is printed.<\/p>\n<\/div>\n\n
Complexity Analysis<\/h2>\n
The time complexity of this problem is O(N) since all elements of the array are visited once. Furthermore, the space complexity is O(1), as only one additional variable is used to store the result, making it very efficient.<\/p>\n
Optimization<\/h3>\n
The structure of the given problem is approached in the most optimized manner, and there is no need for further optimization. This is because all elements are iterated through only once to obtain the result.<\/p>\n<\/div>\n
\n
Conclusion<\/h2>\n
This course has taught us how to efficiently handle arrays through the problem of calculating the sum of remainders, as well as the basic input\/output and loop usage in Kotlin. Practicing such foundational problems will greatly help in building the basics for coding tests. I hope you continue to solve various problems and enhance your skills.<\/p>\n<\/div>\n
<\/body><\/p>\n","protected":false},"excerpt":{"rendered":"
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